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ARIJIT CHANDA

· started a discussion

· 1 Months ago

incomplete solution (Question:279122.1)

incomplete solution

Question:

DIRECTIONS: Answer the questions based an the following information.

In a gym, there are 5 different weights A, B, C, D and E.

i. B weighs twice as much as C.

ii. A weighs 4 times as much as B.

iii. D weighs 3 times as much as E.

iv. E weighs five and half times as much as B.

The weights are measured in pounds and all of them have integral values.

Which of the following can be the total weight of the lightest and the heaviest weights?

Options:
A)

304 pounds

B) 202 pounds
C)

104 pounds

D)

274 pounds

E)

442 pounds

Solution:
Ans:(e)

The total of the lightest and the heaviest weight is n + 33n = 34n.

Since all the weights have an integral value, the total value of these 2 weights has to be a multiple of 34.

Among the options given, only 442 is a multiple of 34.

Knowledge Expert

· commented

· 1 Months ago

The total of the lightest and the heaviest weight is n + 33n = 34n.

Since all the weights have an integral value, the total value of these 2 weights has to be a multiple of 34.

Among the options given, only 442 is a multiple of 34.
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