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Rajshree Kumari

· started a discussion

· 1 Months ago

plz explain clearly or in other way

Question:
A says to B “I am twice as old as you were when I was as old as you are”. The sum of their ages is 63 years. Find the difference of their ages.
Options:
A) 27 years
B) 21 years
C) 9 years
D) 6 years
Solution:

Ans:(c) A   B

Present age  2x   y

Some years before  y   x

Here,2x – y = y – x

2x + x = y + y

3x = 2y

 \(\frac{x}{y}\) = \(\frac{2}{3}\) 

A : B

2x :  y

2 × 2 : 3

Present age 4  :  3

Now, the required difference in ages = \(\frac{63\times(4-3)}{(4+3)}\)  = 9 years

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