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gaurav

· started a discussion

· 1 Months ago

how (Question: 148476.0 )

please check the solution

Question:
DIRECTIONS: In the following questions, two equations numbered I and II are given. Solve both the equations and given your answer as:


I. P2 + 12P + 27 = 0  


II. q2 + 15q + 54 = 0

Options:
A) If p > q 
B) If p ≥ q
C) If p < q
D) If p ≤ q
E) If p = q or relationship cannot be established
Solution:

Ans: (e) 

P2 + 12P + 27 = 0

P2 + 9P + 3P + 27 = 0

(P + 9)(P + 3) = 0

P = -9, -3

q2 + 15q + 54 = 0

q2 + 9q + 6q + 54 = 0

(q + 9)(q + 6) = 0

q = -9, -6


gauravgupta4532

· commented

· 1 Months ago

Yet to be approved!

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct
X Y
-9 = -9
-9 < -6
-3 > -9
-3 > -6
So, we can't established the relation between them.

Best wishes
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