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bharat

· started a discussion

· 1 Months ago

how 12C2 / 12C2 = 1/66 ? (Question: 122185.0 )

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Question:
A box contains 2 blue balls, 4 red balls, 5 green balls and 1 yellow ball. If two balls are picked randomly, what is the probability that both are blue?
Options:
A) \(\cfrac{1}{55}\)
B) \(\cfrac{1}{22}\)
C) \(\cfrac{1}{33}\)
D) \(\cfrac{1}{66}\)
E) \(\cfrac{1}{6}\)
Solution:
Required probability =  \(\cfrac{^2C_2}{12C_2}=\cfrac{1}{66}\)  

Divyanshu Arya

· commented

· 1 Months ago

Its worng- correct is-----> 2C2/12C2
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