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Spak

· started a discussion

· 1 Months ago

Great (Question: 98795.0 )

Great job team. really.
I couldn't get the 1st process.
but the alternate process is very simple & useful.
thanks.

Question:
Deepak and soni working together completed a job in 8 days. If deepak worked twice efficiently as he actually did and soni worked \(\cfrac{1}{3}\) as efficiently as she actually did, the work would have been completed in 6 days. Find the time taken by deepak to complete the job alone:
Options:
A) 8 days
B) \(\cfrac{38}{55}\) days
C) \(\cfrac{15}{2}\) days
D) 13 \(\cfrac{1}{3}\) days
E) 15 days
Solution:

Let, Deepak complete the work in x days & soni complete the work in y days.

now, from question

\(\frac{1}{x}\)+\(\frac{1}{y}\)= \(\frac{1}{8}\)...(1)

from second condition,

\(\frac{2}{x}+\frac{1}{3y}=\frac{1}{6}\)...(2)

multiply (1) by \(\frac{1}{3}\) and subtract (2) from it .

x = 13 \(\frac{1}{3}\) days i.e. deepak alone can complete work in 13 \(\frac{1}{3}\) days.

kanhaiya jha

· commented

· 1 Months ago

Let, Deepak complete the work in x days & soni complete the work in y days.
now, from question
1/x+1/y= 1/8...(1)
from second condition,
2/x+13/y=1/6...(2)
multiply (1) by 1/3 and subtract (2) from it .
x = 13 and 1/3 days i.e. deepak alone can complete work in 13 and 1/3 days.

ved

· commented

· 1 Months ago

what is the alternate process ??

Anuroop chowdary

· commented

· 1 Months ago

D+S=(1/8)
2D+(1/3)S=(1/6)

S=(1/8)-D

2D+(1/3)[(1/8)-D]=(1/6)

2D+{(1-8D)/24}=(1/6)

48D+1-8D=4

40D=3

D=3/40

SO WORK IS 40/3 i.e 33 1/3
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