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Ganesh Zalte

· started a discussion

· 1 Months ago

Full explanation needed (Question: 181195.0 )

Dear Sir/Mam the full and detail explanation of the question will helpful and beneficial . And a shortcut answer to the same question should be there at the end with separate block for this shortcut explaination, please kindly take it granted

Question:
DIRECTIONS: In the following question, two statements numbered I and II are given, on solving them, we get quantities I and II respectively. Compare both the quantities and choose the correct option. 


Quantity I- A shopkeeper sells an object for 25% profit. If he buys it for 25% less and sells it for Rs 25 less then he earns 25% profit. What is the original cost price?


Quantity II- 5% more is gained by selling a cow for Rs. 1010 than by selling it for Rs. 1000. Find the cost price of the cow.

Options:
A) Quantity I > Quantity II 
B) Quantity I < Quantity II
C) Quantity I ≥ Quantity II
D) Quantity I ≤ Quantity II
E) Quantity I = Quantity II or the relation can’t be determined  
Solution:
Ans: (b) 

From Quantity I,

Let the original cost price of the article be 100x.

Then A.T.Q.

\(\cfrac{125x-25-75x}{75x}\times100=25\)

\(\cfrac{50x-25}{75x}=\cfrac{1}{4}\)

Hence original cost price of the article =100 x=100\(\times\cfrac{4}{5}= Rs\ 80\)


From Quantity II,


1010-1000=10=5 %

Hence cost price= 100 % =100\(\times\)\(\cfrac{10}{5}\)= Rs 200



Knowledge Expert

· commented

· 1 Months ago

Hi, detailed explanation has been given, please click on report and view solution.....only formula need to apply.its not so typical.......
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