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SHRADDHA SANODIYA

· started a discussion

· 1 Months ago

marked price=sp(100-d%)/100 but here it is cp(100+p%)/100=sp not mp

Question:
DIRECTIONS: In the following question, two statements numbered I and II are given, on solving them, we get quantities I and II respectively. Compare both the quantities and choose the correct option. 


Quantity I- Mr. Pandey purchased 200 pieces of mouse at the rate of Rs 440/- per piece. Then he listed the price so as to gain a profit of 35% while selling the mouse he offered a discount of 5%. What is the profit earned in the deal?


Quantity II- A man purchased some articles for Rs. 1,89,542. He sells 3/8 of them at 5% loss. At what profit % did he sell the remaining so that he earns 9% profit overall?

Options:
A) Quantity I > Quantity II 
B) Quantity I < Quantity II
C) Quantity I ≥ Quantity II
D) Quantity I ≤ Quantity II
E) Quantity I = Quantity II or the relation can’t be determined  
Solution:
Ans: (a) 

From Quantity I, 


Marked price =  \(\cfrac{440×135}{100}\) = 594

SP = \(\cfrac{594×95}{100}\) = 564.3

Reqd percentage =  \(\cfrac{124.3}{440}\) × 100 = 28.25%

From Quantity II,


The fraction given is \(\frac{3}{8}\)  . Let this means first 3 are sold at 5% loss

 

3 sold at 5% loss each

To make 9% profit on each of the 8 items means 9 × 8 = 72%

To gain 9% profit on each now the remaining 5 items should be sold at

-15% + 5x = 72%

⇒ 5x= 87%

⇒ x =  \(\frac{87}{5}\)  = 17.4% profit each

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