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Meenu Chauhan

· started a discussion

· 1 Months ago

pl. provide video sol for this ques.

Question:

DIRECTIONS: These questions are based on the following information.


Four children Bittu, Chittu, Kittu and Mittu have four types of fruits mangoes, Oranges, Apples and Bananas. Such that each child has at least one fruit and at most six fruits of one type. They have total of 11 Mangoes, 13 Oranges, 13 Apples and 14 Bananas. Total number of fruits with each child is different. No two of the children has the same number of fruits of any type. No child has the same number of fruits of any two types. We know the following additional information.

(i) The number of Bananas with Bittu is five.

(ii) Chittu has a total of 16 fruits.

(iii) Among the fruits with Kittu, the number of apples is the least and the number of Mangoes is the highest.

(iv) The number of fruits with Kittu is not less than that with Bittu.

(v) The difference between the number of oranges with Chittu and the number of apples with Bittu is two. 

How many Oranges are there with Kittu?

Options:
A)

1    

B)

2

C)

3

D)

4

Solution:

Ans: (d) 

As no child has the same number of fruits of any two types, each child must have a total of at least 10 fruits [1 + 2 + 3 + 4].

Total number of fruits = 11 + 13 + 13 + 14 = 51

From (ii), chittu has 16 fruits.

∴ The total number of fruits with the other three children is 51 - 16 = 35.

∴ The other three children have 10, 11, 14 fruits or 10, 12, 13 fruits.

from (i), Bittu has more than 10 fruits [1 + 2 + 3 + 5]

From (iv) and above results, Kittu has more than 11 fruits. 

From the above three results, Bittu has 11 and Kittu has 14 fruits or Bittu has 12 and Kittu has 13 fruits.

∴ Mittu has exactly 10 fruits.

As there are only 11 mangoes, a child has at most 5 mangoes.

From (iii), and above results, Kittu has 5 mangoes [∴ He has more than 11 fruits]

If he has 14 fruits, then the other fruits must be 2, 3 and 4 in number.

If he has 13 fruits, then the other fruits must be 1. 3 and 4 in number.

In any case, he has 3, 4 and 15 fruits of different types and 1 or 2 apples. 

∴ Kittu has 3 or 4 bananas.

From (i) and as the number of bananas is 14, no child has 6 bananas, sine Bittu and Kittu together have at least 8

bananas.

∴ The number of bananas with the children are 2, 3, 4 and 5.

From (ii), Chittu has 1, 4, 5 and 6 fruits or 2, 3, 5 and 6 fruits,

Also, from the above results, Chittu cannot have 5 or 6 fruits of mangoes or bananas.

∴ The number of oranges and apples with Chittu are 5 and 6 in any order

If he has 5 oranges and 6 apples then from, (v), Bittu will have 3 apples.

∴ Chittu and Bittu together have 9 apples and the other two have a total of 4 apples [1 + 3]

But neither of the remaining two children can have 3 apples as Bittu has 3 apples.

∴ This case is not possible.

∴ Chittu has 6 oranges and 5 apples.

From (v), Bittu has 4 apples.

∴ The other two children have total of 4 [13 – 5 – 4] apples. 

⇒ One of them has 1 apple arid the other has 3 apples.

But Kittu cannot have 3 apples [From (iii)]

∴ Kittu has one apple and Mittu has 3 apples.

∴ Kittu has a total of 13 fruits [1 + 3 + 4 + 5]. 

⇒ Bittu has a total of 12 fruits.

As Chittu has 6 oranges, the other three children have 1, 2 and 4 oranges.

∴ Kittu must have 4 oranges [as he cannot have 3 mangoes]

⇒ Kittu has 3 bananas

As Mittu cannot have 4 mangoes or 4 oranges he must have ad 4 bananas.

⇒ Chittu has 2 mangoes.

∴ The final distribution is as follows:

Child →

Fruit ↓

Bittu

Chittu

Kittu

Mittu

Total

Mangoes

½

3

5

2/1

11

Oranges

2/1

6

4

½

13

Apples

4

5

1

3

13

Bananas

5

2

3

4

14

Total

12

16

13

10

51

Tasleem Begum

· commented

· 1 Months ago

has the video solution been updated?????

Knowledge Expert

· commented

· 1 Months ago

Dear student
Thanks for showing interest for video solution.Soon we will be updating the same .

Regards
Team TR

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