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Shinjini

· started a discussion

· 1 Months ago

doubt (Question: 78020.2 )

As in the next question those two pairs make complementary pair so why that logic doesn't apply here ?? it may be either 2 or 4 and 1 & 3

Question:
DIRECTIONS: In each of these questions the symbols @, #, $, % and * are used as different meanings as follows.


I.    ‘P @ Q’ means ‘P is not smaller than Q’.


II.    ‘P # Q’ means P is not greater than Q.


III.   ‘P $ Q’ means ‘P is neither smaller than nor greater than Q’.


IV.   ‘P % Q’ means ‘P is neither smaller than nor equal to Q’.


V.     ‘P * Q’ means ‘P is neither greater than nor equal to Q’.



In each question, four statements showing relationships have been given, which are followed by four conclusions I, II, III and IV. Assuming that the given statements are true, find out which conclusion(s) is/are definitely true.

Statements:

R @ J, J * F, F # M, M % V


Conclusions:

I.   J % V

II.  R @ M

III. J # V

IV. R * M

Options:
A) Either I or III is true
B) Either II or IV is true
C) I and III are true
D) Either I or III and either II or IV are true
E) None is true.
Solution:

Given,

@ = >

# = <

$ = =

% = >

* = <


Statements:

R > J, J < F, F < M, M > V


On combining the statements:

R > J 

M > F > J  

M > V 

 

Conclusions:

I.   J > V   (false independently but making complementary with III)

II.  R > M  (false independently but making complementary with IV)

III. J < V   (false independently but making complementary with I)

IV.  R < M  (false independently but making complementary with II)


Hence, Either I or III and either II or IV are true

Knowledge Expert

· commented

· 1 Months ago

Conclusions:
I. J > V (false independently but making complementary with III)
II. R > M (false independently but making complementary with IV)
III. J < V (false independently but making complementary with I)
IV. R < M (false independently but making complementary with II)

Hence, Either I or III and either II or IV are true
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