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Priyadharshini

· started a discussion

· 1 Months ago

Directions (Question:326665.0)

Could someone explain this with a diagram clearly?

Question:
Sunil walked 40 m towards South, then took a left turn and walked 70 m. Now, he took a left turn and walked 40√3 m. Finally, he took a turn of 150o in anticlockwise direction and walked 80 m. How far and in which direction is he now from the starting point?
Options:
A) 50 m, South—west 
B) 70 m, South—east 
C) 50m, South—east
D) 70 m, South—west
E) None of these
Solution:
Ans: (c)

\(\therefore CE \ \ = \ \ \sqrt[]{(80)^2-(40\sqrt[]{3}})^2 \ \ \ = \ \ 40m\)

Therefore, = AE = \(\therefore CE \ \ = \ \ \sqrt[]{40^2+30^2} \)

Hence, Sunil is 50 m to the south-east of his initial position.

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