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suraj rajput

· started a discussion

· 1 Months ago

dd (Question: 99433.0 )

explain how u count effi. in question no.32 in mock test

Question:

Two workers undertake to do a job. The second worker started working 2 hours after the first. Five hours after the second worker has begun working there is still 9/20 of the work to be done. When the assignment is completed after another 5 hours, it turns out that first worker has done 60% of the work, while second worker has done rest of the work. How many hours would take each one to do the whole job individually?

Options:
A) 10 hours and 12 hours   
B) 15 hours and 10 hours
C) 20 hours and 25 hours 
D) 18 hours and 20 hours
E) None of these
Solution:
Go through option. Consider choice (c). 

Efficiency of first worker = 5% 

Efficiency of second worker = 4% 

∴ In 7 hours first worker completed 35% work 

In 5 hours second worker completed 20% work 

Thus, work completed = 55% 

Remaining work = 45%

Hence, one condition is satisfied. 

Again, they will take 5 more hours to complete 45% work 

\(\big[ \cfrac{45}{4+5}=5\big]\)

Thus, first person completes 7 × 5 + 5 × 5 = 60% work and second person completes 5 × 4 + 5 ×4 = 40% work 

Hence, second condition is also satisfied. Hence, correct option is (c).

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