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saloni sharma

· started a discussion

· 1 Months ago

confussion (Question: 99948.0 )

why we take here 5 digit smallast value.

Question:
The largest four digit number exactly divisible by each of 12, 15, 18 and 27 is:
Options:
A) 9690
B) 9720
C) 9930
D) 9960
E) None of these
Solution:

LCM of 12, 15, 18 and 27 = 540

The least 5 digit number is 10000,

which when divided by 540 leaves 280 as the remainder.

Hence, 10000 – 280 = 9720 which will be the highest possible 4 digit number which will be completely divisible by 540.

kanhaiya jha

· commented

· 1 Months ago

:)

saloni sharma

· commented

· 1 Months ago

thanks ....

kanhaiya jha

· commented

· 1 Months ago

We need to find the largest four digit number,

so first , calculate the LCM of 27,18,12 and 15.

We know that the largest four digit number is 9999.

So,to find out the largest four digit number divisible by these numbers ,we will divide 9999 by the LCM calculated.

LCM(27,18,12,15)=540

9999= 540*18+279

So,to make it perfectly divisible we will subtract 279 from 9999.

9999-279=9720

Therefore,9720 is the largest four digit number perfectly divisible by 27,18,12 and 15.
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