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Anku

· started a discussion

· 1 Months ago

complete solution (Question:117736.0)

plz give commplete solution

Question:
Four bells ring at intervals 4, 6, 8 and 14 seconds. They start ringing simultaneously at 12.00 O’clock. At what time will they again ring simultaneously?
Options:
A) 12 hrs 2 min 48 sec
B) 12 hrs 3 min
C) 12 hrs 3 min 20 sec
D) 12 hrs 3 min 44 sec
E) None of these
Solution:
Ans: (a) 

LCM of 4, 6, 8, 14 seconds is 

4 = 2\(\times\)2

6= 2\(\times\)3

8= 2\(\times\)2\(\times\)2

14= 2\(\times\)7

LCM =2\(\times\)2\(\times\)2\(\times\)3\(\times\)7 = 168 seconds

As they ring simultaneously after 168 seconds and at 12.00 o'clock they rang together 

so they will again ring together after 168 seconds

or 2 minutes 48 seconds of 12.00 o'clock

i.e. 12 : 02 : 48 o'clock .


Knowledge Expert

· commented

· 1 Months ago

Dear student
Here is the updated solution:
LCM of 4, 6, 8, 14 seconds is 168 seconds
As they ring simultaneously after 168 seconds and at 12.00 o'clock they rang together
so they will again ring together after 168 seconds
or 2 minutes 48 seconds of 12.00 o'clock
i.e. 12 : 02 : 48 o'clock .

Regards
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