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Anindita

· started a discussion

· 1 Months ago

the correct ans is b not a

Question:
The population of a town in the first year increases by 10%.In the next year it decreases by 10%, once again in the third year it increase by 10% and in the fourth year it decrease by 10%. If the present population be 20,000 then the population after four years will be: 
Options:
A) 16,902 
B) 19,602 
C) 20,000
D) None of these
Solution:
Ans: (b) Population after 4 year 

= \(20,000 \left (1+ \cfrac {10}{100} \right )\left (1- \cfrac {10}{100} \right )\left (1+ \cfrac {10}{100} \right )\left (1- \cfrac {10}{100} \right )\)

= 20,000 (1.1) (0.9) (1.1) (0.9)

= 20,000 × 1.21 × 0.81 = 19,602

kanhaiya jha

· commented

· 1 Months ago

Required population = 19,602

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