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Koppisetti Prajnesh

· started a discussion

· 1 Months ago

Brief solution (Question:99422.0)


Let x/- be the cost price of OU.
Given that 9.09% is profit
So ,ratio is 9.09/100=.0909
But .0909 is the ratio value of 1/11.
Here numerator implies profit part and denominator indicates cost price part.

Now sp = cp+profit ,So, selling price part becomes 1+11=12.
But we are selling at 48/-
Therfore
48=12/11 of Cp
=> overall Cp is 44/-
And now use mix and allegation
48 x
\ /
44
/ \
____ 4


But given that they are mixed in the ratio SU :OU =12:3 = 4 :1
The ratio 4:1 can be written as 16 :4.
Therefore

48 x
\ /
44
/ \
16 4

=> 44 - x= 16
=> x =28/-.

Question:

A trader sells two brands of petrol; one is Ordinary unleaded (OU) and other one is Super unleaded (SU). He mixes 12 liters of SU with 3 liters of OU and by selling this mixture at the price of SU he gets the profit of 9.09%. If the price of SU be \(\unicode{x20B9} \)48 per liter, then the price of OU is:

Options:
A) \(\unicode{x20B9} \)38 per litre
B) \(\unicode{x20B9} \)42 per litre
C) \(\unicode{x20B9} \)28 per litre
D) \(\unicode{x20B9} \)35 per litre
E) None of these
Solution:

SP = \(\cfrac{12}{11}\)of CP

48 =\(\cfrac{12}{11}\) of CP ⇒   CP = 44

Now, by allegation

(Since ration of SU to OU =\(\cfrac{12}{3}\)= 4 : 1)



∴k = 44 – 16 = 28

Thus the price of  OU is Rs. 28/liter.

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