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Vande Mataram

· started a discussion

· 1 Months ago

B is the answer. (Question: 111646.0 )

B is the answer.

Question:
DIRECTION : In the given question two equations numbered I and II are given. You have to solve both the equations and Give answer if


I. x2 + 7x + 12 = 0

II. y2 + 6y + 8 = 0

Options:
A) x < y
B) x ≤ y
C) x > y
D) x ≥ y
E) x = y or the relationship cannot be established
Solution:

From equation I,

x2 + 7x + 12 = 0

x2 + 3x + 4x + 12 = 0

(x + 3) (x + 4) = 0

x = -3,  -4

From equation II,

y2 + 6y + 8 = 0

y2 + 2y + 4y + 8=0

⇒ (y +2) (y + 4) = 0

y = -2, -4

∴, No relation

Knowledge Expert

· commented

· 1 Months ago

How option(b) can be the answer????????

See: From equation I,
x2 + 7x + 12 = 0
x2 + 3x + 4x + 12 = 0
(x + 3) (x + 4) = 0
x = -3, -4
From equation II,
y2 + 6y + 8 = 0
y2 + 2y + 4y + 8=0
⇒ (y +2) (y + 4) = 0
y = -2, -4

-3<-2
-4<-2
-3>-4
-4=-4

Did u see ever that all the three symbols of inequality occur together????

Ans: Now, thats why No relationship can be established.
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