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DARSHAN

· started a discussion

· 1 Months ago

32 (Question:581805.0)

soln

Question:

DIRECTION: In the given question three expressions numbered I, II and III are given. You have to solve all the expressions and give answer :

(i) STATEMENT (A):

16 \(\frac{2}{3}\)% of 420 + \(\sqrt{4489} - \sqrt{729} \)


(ii) STATEMENT (B):

2 \(\frac{4}{5}\)+ 3 \(\frac{6}{5}\) × 5 \(\frac{2}{5}\) \(\div\) \(6 \frac{1}{2}\)


(iii) STATEMENT (C):

\(\sqrt{6^2 × 12 -5 × 7 + 4^2 \ \ \ \ \ \ \ \ \ }\)

Options:
A) A > C > B
B) A > B > C
C) A < B < C
D) A = B > C
E) A > B < C
Solution:

Ans. (a)

FROM STATEMENT (A) :

16 \(\frac{2}{3}\)% of 420 + \(\sqrt{4489} - \sqrt{729} \)

= ( \(\frac{1}{6}\)× 420) + 67 - 27

= 70 + 40

= 110


FROM STATEMENT (B) :

2 \(\frac{4}{5}\)+ 3 \(\frac{6}{5}\)  × 5 \(\frac{2}{5}\) \(\div\) 6 \(\frac{1}{2}\)

= 2 \(\frac{4}{5}\)+ 3 \(\frac{6}{5}\) × \(\frac{27}{5}\) × \(\frac{2}{13}\)

= \(\frac{14}{5}\) + \(\frac{21}{5}\)× \(\frac{27}{5}\)× \(\frac{2}{13}\)

= \(\frac{14}{5} + \frac{567}{25} × \frac{2}{13}\) 

= \(6\frac{7}{25}\)


FROM STATEMENT (C) :

\(\sqrt{6^2× 12 - 5 × 7 + 4^2\ \ \ \ \ \ \ \ \ \ }\)

\(\sqrt{36 × 12 - 35 + 16 \ \ \ \ \ \ \ }\)

\(\sqrt{432 -51 \ \ \\ \ \ \ }\)

\(\sqrt{381 \ \ }\)

= 19.5 

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