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RAUNAK

· started a discussion

· 1 Months ago

121457.0 (Question: 121457.0 )

is there another way to solve this???

Question:

A bag contains 6 white and 4 red balls. Three balls are drawn one by one without replacement. What is the probability that 2 are red and 1 is white?

Options:
A) 0.1
B) 0.2
C) 0.3
D)

0.4


E)

0.5


Solution:

Ans: (c) The following combinations are possible. First white, second red, third red, or first red, second white, third red or first red, second red, third white  


So the probability,


Scholastic

· commented

· 1 Months ago

4c2* 6c1 / 10c3 = 0.3

kanhaiya jha

· commented

· 1 Months ago

This is the simplest way - The following combinations are possible-First white, second red, third red, or first red, second white, third red or first red, second red, third white ..
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