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Harsh Vardhan Singh Bhati

· started a discussion

· 1 Months ago

wtf!!!!!!! (Question: 257141.0 )

bc tumhari maths ki baat bad me karege, english kaha se seekhi??? did you read question???... it clearly mentions that perpendiculars are drawn from s on the sides PQ and PR... tune toh solution me question ki hi kaya palat di... bhai pese mai bhul jauga, parr future kharab ho gaya toh dil se itni gaaliya duga k poore webpage me virus bhar jayege

Question:

An isosceles triangle PQR is right angled at Q. S is a point inside the triangle PQR, M and N are the foot of the perpendiculars drawn from S on the sides PQ and PR respectively. If PM = 8 cm, PN = 6 cm and ∠QPS = 15°, sin75° = ?

Options:
A)

223    

B)

43    

C)

\(\frac{3√3}{8}\) 

D)

833    

Solution:

Ans: (c)


In ∆ PMS

Sin 75° = \(\cfrac{PS}{8}\)

And in ∆ PNS

Sin 60° = \(\cfrac{PS}{6}\)

PS = 6 × \(\cfrac{√3}{2}\) = 3√3 cm

∴ sin75° = \(\cfrac{PS}{8}\) = \(\cfrac{3√3}{8}\)

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