wrong solution (Question: 111051.0 )

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anmol tyagi

· started a discussion

· 1 Months ago

wrong solution (Question: 111051.0 )

you have written HG=AB-2
where have you mentioned GB=2?
and if we find the height of the triangle, it comes out as 3.
So, HG=height of the isosceles triangle = 3
therefore, area of HOG=1/2(4x3)
so total area = 84-2x(6) = 72 units.

Question:

In the given frame work, it being given that OG = OF, then area of the frame work is :

Options:

A) 64m²

B) 62 m²

C) 60 m²

D) 58 m²

Solution:

Ans: (a) Area of frame work ABCDEFOGHA

= area of rectangle ABCD - 2 (area of \(\triangle\) HOG)

HO = AO - AH

= 6 - 4 = 2 m

HG = AB - 2

= 7 - 2 = 5m

Area of frame-work

\(=12\times7-2\left ( \cfrac{1}{2}\times 5\times4\right )\)

\(=84-320=64m^2\)

Rajat Raj Verma

· commented

· 1 Months ago

Ram Ram Bhai
Shubham And Rajat

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