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Giridhari das

· started a discussion

· 1 Months ago

suppose the centre of the triangle is O. now Angle OAT will be 90. and OAB will become 15(90-75=15). and also angle OBA=15. so AOB will become (180-15-15)=150. Now from theorem "Angle subtended by the same chord at centre is twice to that of angle subtended at any other point on the circumference. so angle ACB will become 75.
why this solution is wrong?

Question:

AB is a chord to a circle and PAT is 'the tangent to the circle at A. If \(\angle \)BAT = 75º and \(\angle \)BAC = 45º, C' being a point on the circle, then \(\angle \)ABC is equal to –

Options:
A) 40º
B) 45º
C) 60º
D) 70º
Solution:
Ans: (c)


Knowledge Expert

· commented

· 1 Months ago

Hi Shubham, angle ABC has been asked in the question.....not angle ACB.......Thats it....

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