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anmol tyagi

· started a discussion

· 1 Months ago

suno.
Dekho beta idhar aao
if it is of the form [2m, m2-1,m2+1], then for m=1. the triplet is
[2,0,2].
also, [2,3,5] is no triplet. wo [3,4,5] hota hai, which is at m=2
hame pata hai sharaab choddna asaan nahi. But ham tumhari madat karenge. But beta kuch bhi mat likh dia karo


Question:

If three sides of a right-angled triangle are integers in their lowest form, then one of its sides is always divisible by– 

Options:
A)

2

B)

8

C)

7

D)

None of these

Solution:

Ans:(a) A Pythagorean triplet is always in the form [2m, m2 â€“ 1, m2 + 1] m ïƒŽZ

 [2, 0, 2] for m = 1

   [4, 3, 5] for m = 2

One of them is always divisible by 2.

Knowledge Expert

· commented

· 1 Months ago

Dear student,
We are resolved it


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