Simple solution (Question: 108755.0 )

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Nikhil Manohar

· started a discussion

· 1 Months ago

Simple solution (Question: 108755.0 )

Tom started 50 min earlier. So pages covered = 30 x 50 ÷ 60 = 25
This should be covered by the 2nd one with relative speed
So time taken = 25 ÷( 40 - 30) = 2 hrs 30 mins
So they will read the same page at 5:20 + 2 hrs 30 mins
= 7:50 hrs

Question:

Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?

Options:

A) 9 : 30

B) 9 : 00

C) 8 : 40

D) 7 : 50

Solution:

Ans: (d) Lets say they met at page x.
So time taken by Tom to read x pages = \(\frac{x}{30}\) hours
So time taken by Jan to read x pages =\(\frac{x}{40}\)hours
But the difference between their start is\(\frac{5}{6}\) hours
So \(\frac{x}{30}\) - \(\frac{x}{40}\) = \(\frac{5}{6}\).

x = 100
Jan will read 100 pages in 2:30 hours. So 5:20 + 2:30 = 7:50

prayag

· commented

· 1 Months ago

This one is easy to understand.

Harish Kumar

· commented

· 1 Months ago

more situational

ADITYA SINGH

· commented

· 1 Months ago

this is much better

vishwanath

· commented

· 1 Months ago

thnaks nikhil, i was also thinking of same how to solve it by relative funda.....

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