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Siddhartha Ray Choudhuri

· started a discussion

· 1 Months ago

Total Distance = 300Km ; Total Time= 4hr ;

Train Car Time
60Km 240Km 4hr

+40Km -40Km +10Min

*5 *5 *5
= = =
+200Km -200Km +50Min

300Km 0Km 4Hr+60Min=5Hr

So, Speed of Train = 300Km/5hr =60Km/Hr (Ans)

Also,
60Km/60Kmph + 240Km/x Kmph = 4Hr
240Km/x Kmph = 3Hr
x = 80Km/Hr (Speed of Car)

Question:
Ravi travels 300 km, partly by train and partly by car. He takes 4 hrs to reach. If he travels 60 km, by train and rest by car, he will take 10 minutes more if he were to travel 100 km by train and rest by car. The speed of the train is :  
Options:
A) 50 km/hr.
B) 60 km/hr.
C) 100 km/hr.
D) 120 km/hr.
Solution:

Take the train's speed as x and the car's speed as y. Since time = dist/speed, 
Case 1: 
time = 4hrs, train travel = 60km therefore car travel = 240km 
4 = 60/x + 240/y. 
Case 2: 
time = 4 1/6 hrs(4 hrs + 10/60 hrs) = 25/6 hrs, train travel = 100 km therefore car travel = 200 km 
25/6 = 100/x + 200/y. 

Using Simultaneous Linear Equations, 
1. 4 = 60/x + 240/y. 
2. 25/6 = 100/x + 200/y. 
Multiplying (1) by 5 and (2) by 6, we equate the y values 
Now, 
1. 20 = 300/x + 1200/y. 
2. 25 = 600/x + 1200/y. 
By subtracting (2) from (1), the y terms cancel out 
Result : 
-5 = -300/x 
x = -300/-5 = 60 km/hr 

Hence final answer is: 
The speed of the train is 60km/hr.

RAVI KUMAR

· commented

· 1 Months ago

is anyone there?

RAVI KUMAR

· commented

· 1 Months ago

PLS help me understand this question TEAM PARAMOUNT......
THE shortcut method is good but i m unable to it.....

RAVI KUMAR

· commented

· 1 Months ago

i m still not able to get it.... can anyone pls elaborate the solution further...............

bipin vas

· commented

· 1 Months ago

thanks buddy

Das Sn

· commented

· 1 Months ago

great solution..thnk you... where we can find these solution more?

Priyanka

· commented

· 1 Months ago

very nice solutions. Thank you:)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Your solution is also good.

Best Wishes
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