Problem of punctuation in the question. (Question: 186299.0 )

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Alakh Sundaram

· started a discussion

· 1 Months ago

Problem of punctuation in the question. (Question: 186299.0 )

Wrong use of comma and full stop has completely changed the question. In the present form it seemed there are 3 parts to the question, though the fact is there are only two. It took me some time before I could figure out. Please don't do this as it wastes time.

Question:

Ravi travels 300 km, partly by train and partly by car. He takes 4 hrs to reach. If he travels 60 km, by train and rest by car, he will take 10 minutes more if he were to travel 100 km by train and rest by car. The speed of the train is :

Options:

A) 50 km/hr.

B) 60 km/hr.

C) 100 km/hr.

D) 120 km/hr.

Solution:

Take the train's speed as x and the car's speed as y. Since time = dist/speed,
Case 1:
time = 4hrs, train travel = 60km therefore car travel = 240km
4 = 60/x + 240/y.
Case 2:
time = 4 1/6 hrs(4 hrs + 10/60 hrs) = 25/6 hrs, train travel = 100 km therefore car travel = 200 km
25/6 = 100/x + 200/y.

Using Simultaneous Linear Equations,
1. 4 = 60/x + 240/y.
2. 25/6 = 100/x + 200/y.
Multiplying (1) by 5 and (2) by 6, we equate the y values
Now,
1. 20 = 300/x + 1200/y.
2. 25 = 600/x + 1200/y.
By subtracting (2) from (1), the y terms cancel out
Result :
-5 = -300/x
x = -300/-5 = 60 km/hr

Hence final answer is:
The speed of the train is 60km/hr.

Knowledge Expert

· commented

· 1 Months ago

Hi, Thanks for the feedback........we fixed it.......

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