p (Question: 111644.0 )

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satish bhakher

· started a discussion

· 1 Months ago

p (Question: 111644.0 )

its a blunder to buy ur test series at the time of mains is very close ............u make me feel depressed........ wrong content.. irrelevant pattern ... so many questions related to equations which ssc never asked before.........

Question:

The adjacent sides of a parallelogram are 2a and a. If the angle between sides of parallelogram is 60°, then one of the diagonals of the parallelogram is:

Options:

A) 3a

B) 2a

C) \(\sqrt[]{7}a\)

D) \(\sqrt[]{5}a\)

Solution:

Ans: (c)

Clearly

\(\angle \)ABC = 120°

From \(\triangle\)CAB,

cos B = \(\cfrac{C^2+a^2-b^2}{2ca}\)

we get

cos (180^o- 60^o) =\(\cfrac{4a^2+a^2-AC^2}{2\times2a\times a}\)

or \(-\cfrac{1}{2}=\cfrac{5a^2-AC^2}{4a^2}\)

or -2a² = 5a² - AC²

or AC²=7a²

\(\therefore AC =\sqrt{7}a\)

Knowledge Expert

· commented

· 1 Months ago

Dear Student, Questions are made according to the pattern of the question paper. Thanks and Regards Team TR

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