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Sudakshina ghosh

· started a discussion

· 1 Months ago

if angle APB=130 then angle BCA should be 115. Then ans will be 230 for angle BQD. If angle APB is 130 then any angle on the circumference of the circle centered P will be 65 then according to circular quadrilateral theorem angle BCA is 115(180-65). please reply sir for the doubt.

Question:

Two circles with centres P and Q intersect at B and C. A, D are points on the circles with centres P and Q respectively such that A, C,D are collinear. If ∠APB = 130° and ∠BQD =  xo, then the value of x is:

Options:
A) 65°
B) 130°
C) 195° 
D) 135°
Solution:

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