April 2, 2025
Overview: Nearly half of the questions in the IPMAT Quantitative Ability MCQ section are tricky. Discover more with our IPMAT Question Paper Analysis and Solutions for the past years and refine your strategy for IPMAT 2025 with essential insights.
The Indian Institute of Management (IIM) conducts the Integrated Program in Management Aptitude Test (IPMAT) annually to provide admission to the five-year integrated program in management.
Going through the previous year's paper analysis will help you better understand the essential topics to focus on for better results.
Our experts have curated the past five years of IPMAT question paper analysis and solutions in this post.
The takeaways from this post can immensely help you streamline your preparation to a result-oriented pathway and also give you an idea about the number of questions asked from each subject, the difficulty level of the paper, the type of questions, and more.
Before checking out IPMAT Question Paper Analysis and Solutions, let's see the IPMAT exam analysis trend.
The following points explain the analysis of the IIM IPM exam, including its mode, sections involved, nature of questions, and more.
As per the Exam Pattern for IPMAT, 50% of the question paper comprises the quantitative section (including MCQs and short answer-type questions).
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As per the previous year's trends, the IPMAT verbal ability section questions do not test your conventional English language or ask direct vocabulary questions like antonyms, synonyms, analogies, etc.
Instead, the verbal questions test your overall expertise in English, using question types like words and phrases and fill-in-the-blanks, and your capability to use contextual vocabulary.
Check out the detailed IPMAT question paper analysis and solutions for the Verbal Ability section from the post below.
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To help you understand the type of questions asked in the quantitative aptitude (short answer) section, we have provided a few sample questions curated from the previous year's IPMAT question papers.
You can try to solve them to understand better the difficulty level and type of questions asked in the exam.
Q1.) In a division problem, the product of quotients and the remainder is 24, while their sum is 10. If the divisor is 5 then the dividend is __________. (IPMAT 2020)
Solution: In this problem, we have been given that the product of the quotient(q) and the remainder(r) is 24. i.e q x r = 24 -( i )
And it is also given that their sum is 10, i.e q + r = 10 -( ii )
Divisor(d) = 5.
( i ) and ( ii ) represent the sum and product of a quadratic equation. From ( ii ) putting r = q - 10, in ( i ), we will get q x (10 - q) = 24, i.e q2-10q + 24 = 0, which will give
q = 6 or 4.
Therefore, one will be 6, and the other will be 4. We do not know yet whether the quotient is 6 and the remainder is 4 or vice versa. We know that Dividend(n) = divisor(d) x quotient(q) + remainder(r) .
From the given data, n = 5 x q + r. - ( iii ),
As the divisor is 5, we infer that the remainder obviously will be smaller than 5. Therefore, the remainder will be 4, and the quotient will be 6. Putting the above-decided value in ( iii ). n = 5(6) + 4 , therefore n = 34.
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Q2.) The shortest distance from the point (-4,3) to the circle x2 + y2 = 1 is __________. ( IPMAT 2020 )
Solution: In this question, we have been given the equation of a circle and the coordinates of a point.
From the standard equation of a circle, i.e x2 + y2 = a2, we have a = 1.
The shortest distance of the point P(-4, 3) will be from point P to the point where a straight line drawn from P to the circle's origin intersects the circle. As shown in the figure below, the shortest distance is PM.
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Q3.) The value of
Q4.) The minimum value of f(x)=|3-x|+|2+x|+|5-x| is equal to __________.
Solution: Form f(x)=|3-x|+|2+x|+|5-x| We know that critical points would be x = 3 , x = -2 , and x = 5.
The slope of the line changes at these critical points.
Example
Now, we need to select the critical point with the lowest value of the y-axis. From the figure above, f(3) will have the lowest value.
f(3) = |3 - 3|+|2 + 3|+| 5 - 3|
f(3) = 0 + 5 + 2 .
f(3) = 7.
Hence, the answer is 7.
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Q5.) Ashok purchased pens and pencils in the ratio 2/3 during his first visit and paid Rs. 86 to the shopkeeper. During his second visit, he purchased pens and pencils in the ratio of 4: 1 and paid Rs. 112. The cost of a pen, as well as a pencil in rupees, is a positive integer. If Ashok purchased four pens during his second visit, then the amount he paid in rupees for the pens during the second visit is __________. (IPMAT 2020)
Solution: We have been given that when the person spends Rs. 86, the ratio of pen and pencil is 2:3.
And when he pays Rs. 112, the ratio of pens to pencils is 4:1. In this visit, the total number of pens is 4.
Let x be the price per pen and y be the price per pencil.
Therefore, we have,
4x + y = 112
2x + 3y = 86 (From first visit)
It is in Ratios, so it can be,
4x + 6y = 86 (or)
6x + 9y = 86 (or)
8x + 12y = 86, and so on.
As we know, 4x + y = 112, we can infer that 4x + 6y = 86 is not possible; hence, all the equations after this are impossible.
So now we have,
4x + y = 112
2x + 3y = 86
Solving the above equation, we will get y = 12.
Therefore 4x + 12 = 112
=> 4x = cost of pens = 112 -12 = 100
Hence, the answer is 100.
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Q6.) In a four-digit number, the product of the thousands digit and units digit is zero, while their difference is 7. The product of the middle digits is 18. The thousand digit is as much more than the unit digit as the hundreds digit is more than the tens digit. The four-digit number is __________.
Solution: Let the four-digit number be ABCD. D is the unit place number, C is the tens digit number, B is the hundreds digit number, and A is the thousand digit number.
Given data
This implies that one will be zero; as A is the rightmost place, its value cannot be zero.
Therefore, D = 0.
As D = 0, A will be 7.
B and C can only hold values from 0-9; considering the possible combinations, BC can be 92( or 29) or 63(or 36).
Hence, the answer is 7920.
Q7.) Two friends run a 3-kilometer race along a circular course of 300 meters. If their speeds are in the ratio 3:2, the number of times the winner passes the other is __________.
Solution: Let the speed of the fast one be 3x and the speed of the slow one be 2x.
Time required for the fast one to cover one complete round = tf = 300/3x
Time required for the slow one to cover one complete round = ts = 300/2x
To find out the time at which both meet for the first time, we need to find the LCM of tf and ts
Tmeet = 300/x (lcm of tf and ts)
Distance traveled by the fast one when they meet = Tmeet * speed of fast one
= 300/x * 3x
= 900 m
Therefore, they will first meet when the fast one has covered 900m, then at 1800 m, and then for the last time at 2700 m.
Therefore, the winner will pass the slow one precisely 3 times.
In this section, the difficulty level of questions will be easy to moderate. Therefore, learning Short tricks to attempt the Quantitative Aptitude Section will help you fetch more marks than others.
Check out the questions that can be asked in the quantitative ability MCQ section of the post below.
Q1.) The probability that a randomly chosen factor of 1019 is a multiple of 1015 is
Solution: Given number is 1019, the factors of the given number are 219 x 519
Therefore, the total factors of 1019 are (19 + 1)(19 + 1) = 400.
Multiples of 1015 are 215 x 515; This is of the form 2x × 5y
We need multiple numbers of 2x × 5y and a factor of 219 × 519. Therefore, the possible values of x = 15 , 16 , 17 ,18 , 19
Possible values of y = 15 , 16 , 17 ,18 , 19
Therefore there are five possible values of x and five possible values of y.
Favourable outcome = 5 * 5 = 25
Total number of outcomes = 400
Probability = 25/400 = 1/16.
Hence, the correct option is option D.
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Q2.) The number of acute-angled triangles whose sides are three consecutive positive integers and whose perimeter is at most 100 is
Solution: We have been given three conditions:-
Let's take random values for three consecutive integers: 1, 2, 3
This selection is impossible as it does not satisfy the first condition that the sum of two sides of a triangle should be greater than the third side. Therefore, we rule this out. : 2, 3, 4
The first condition is satisfied, but the second condition, i.e., Acute angle property, is the sum of the square of any two sides has to be greater than the square of the third side 22 + 32 > 42
As 13 < 16. (So this condition is also not satisfied) : 3, 4, 5
The first condition is satisfied, but the second condition, i.e., Acute angle property, is the sum of the square of any two sides has to be greater than the square of the third side 32 + 42 > 52
As 25 = 25. (So this condition is also not satisfied) : 4, 5, 6
Since all the abovementioned conditions are satisfied, 4,5,6 will be our first consecutive integer set. Then (5,6,7) works, and so on.
When the numbers become larger squares, they become increasingly larger
So after 4,5,6, all sets will satisfy condition 2.
Now, we need to know the last possible consecutive number set based on the third condition.
Which gives 32,33,34 -Perimeter is at most 100
Therefore, the first 3 of the first 32 combinations are ruled out. So, in total, 29 combinations are possible.
Hence, choice B is the correct answer.
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Q3.) The value of cos2 /8+ cos2 3/8 + cos2 5/8 + cos2 7/8 is.
Solution: We know that 58= 2 + 8
And 78= 2 + 38 =
=> cos2 /8+ cos2 3/8 + cos2 (/2 +/8 ) + cos2 (/2 +3/8)
=> cos2 /8+ cos2 3/8 + sin2 /8 + sin2 3/8
=> (cos2 /8+ sin2 /8 )+ (cos2 3/8 + sin2 3/8)
=> 1 + 1
=> 2
Hence, the correct choice is option C.
Q4.) If 112+ 122+132+142+ ..... upto = 26, then the value of 112+132+152+ ..... upto, is.
Solution: Given 112+ 122+132+142+ ..... upto = 26 -(i)
Separation even and odd terms
(112+132+152+ ..... upto ) +(122+142+162+ ..... upto ) = 26
x + 1/4(112+ 122+132+142+ ..... upto ) = 26
x + 1/4(112+ 122+132+142+ ..... upto ) = 26
x + 1/4( 26) = 26 from (i)
x =26(1 - 14)
x =28
Hence the correct choice is option A.
Q5.) A 2 × 2 matrix is filled with four distinct integers randomly chosen from the set {1,2,3,4,5,6}, Then the probability that the matrix generated in such a way is singular is
Solution: The matrix will be singular only if its determinant is zero.
Therefore, the given matrix be
a | c |
b | c |
= |acdb| = ab - cd = 0, Or ab = cd
Using hit and trial from the given set {1,2,3,4,5,6}.
From the above equation, we can infer that b > d
{b, d} ⊂ {1, 2, 4}
If b = 4, d = 2
If b = 2, d = 1
Taking 3 and 6 we observed that only 2 choices were possible i.e {a, b, c, d} = {1, 2, 3, 6} or {a, b, c, d} = {4, 2, 3, 6}. Hence, we can select four numbers from the six in 6C4 = 15 ways.
Therefore, there will be 15 ways to select them and 4! ways to arrange them in the matrix.
So, the total number of matrices that can form is 15 x 4!.
Once we select {a, b, c, d} = {1, 2, 3, 6} or {a, b, c, d} = {4, 2, 3, 6}, for the matrix to be singular, 2,3 or 4,3 should be on the same diagonal. Hence, only â…“ of the arrangements yield a singular matrix.
Only one-third of the arrangements yield a singular matrix, and the others don’t.
Probability of getting a singular matrix = 2( 4! â…“ )154! = 2/45.
Hence, option A is the correct choice.
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Here is a sample IPMAT question paper analysis and solutions from the verbal ability section of the IPMAT Exam. Try solving this question to know how well you can attempt IPM Verbal Ability Questions.
In addition to this question, you are advised to practice more questions from previous years' papers to test your preparation levels.
(Q.1 - 6) Read the following passage and choose the answer that is closest to each of the questions that are based on the passage.
Supposing half a dozen or a dozen men were cast ashore from a wreck on an uninhabited island and left to their own resources, one of course, according to his capacity, would be set to one business and one to another; the strongest to dig and to cut wood, and to build huts for the rest: the most dexterous to make shoes out of bark and coats out of skins; the best educated to look for iron or lead in the rocks, and to plan the channels for the irrigation of the fields. But though their labours were thus naturally severed, that small group of shipwrecked men would understand well enough that the speediest progress was to be made by helping each other- not by opposing each other. They would know that this help could only be properly given so long as they were frank and open in their relations and the difficulties which each lay under properly explained to the rest. So that any appearance of secrecy or separateness in the actions of any of them would instantly, and justly, be looked upon with suspicion by the rest, as the sign of some selfish or foolish proceeding on the part of the individual. If, for instance, the scientific man were found to have gone out at night, unknown to the rest, to alter the sluices, the others would think, and in all probability rightly think, that he wanted to get the best supply of water to his own field; and if the shoemaker refused to show them where the bark grew which he made the sandals off, they would naturally think, and in all probability rightly think, that he didn't want them to see how much there was of it and that he meant to ask from them more corn and potatoes in exchange for his sandals than the trouble of making them deserved. And thus, although each man would have a portion of time to himself in which he was allowed to do what he chose without let or inquiry - so long as he was working in that particular business which he had undertaken for the common benefit, any secrecy on his part would be immediately supposed to mean mischief; and would require to be accounted for, or put an end to and this all the more because, whatever the work might be. Certainly there would be difficulties about it which, when once they were well explained, might be more or less done away with by the help of the rest; so that assuredly every one of them would advance with his labour not only more happily, but more profitably and quickly, by having no secrets, and by frankly bestowing, and frankly receiving, such help as lay in his way to get or to give.
Q1.) When a dozen men are cast away on an imaginary island, the best educated will look for metals in rocks because
Answer: D
Q2.) The author states that any appearance of secrecy or separateness would instantly and justly be considered suspicious. From this statement, we may infer that
Answer: C
Q3.) The instance of the shoemaker who refuses to show his source and asks for more corn and potatoes is an example of
Answer: B
Q4.) According to the author, whatever one's work might be
Answer: D
Q5.) The author believes that for progress to happen
Answer: B
Q6.) The writer makes a hypothesis which can be related to
Answer: A
Q7.) Rearrange the following sentences
Answer: A
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A well-informed preparation strategy is essential to excelling in the Integrated Program in Management Aptitude Test (IPMAT). Here are practical steps based on the IPMAT question paper analysis and solutions:
By following these strategies, drawn from detailed IPMAT question paper analysis and solutions, you can significantly improve your IPMAT performance.
The right preparation approach will help you understand and tackle the exam pattern efficiently.
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