IPM Aptitude Questions & Answers based on Cross Multiplication

Aspirant of IPMAT exam but don't know how to solve lengthy calculations in a matter of seconds? Well, a simple technique named cross multiplication will help you solve complex multiplication problems in less time.

Wondering, how?? Read through the post that will give you a complete insight into cross multiplication, IPM Aptitude Question & Answers based on Cross Multiplication.

Cross Multiplication or Vedic Multiplication is a concept of Vedic maths that enables faster calculation than the usual conventional method. It is based on mental calculation.

As said above, the QA section in IPMAT is a bit difficult, lengthy and time-consuming. Therefore following Maths tips for IPMAT will help maximize your scores.

Let us understand this concept using an example, say 24 X 35.

Step-1: Multiply the one’s digits of both the numbers and then note the ones digit number of the product in the answer.

Here we need to multiply 4 x 5, which would give us 20 and then noting 0(one-digit number of the product) in the answer and taking the tens digit to carry forward.

24

X

35

0

Step-2: Multiply the diagonals and add them together. In this problem, we have 2 x 5 = 10 and 3 x 4 = 12 as the diagonals. Add the results together to obtain 22+2(a carryforward), write its one digit value down next to 0 and take the tens digit to carry forward.

Step 3: Multiply the digits in the ten’s column together and write the number to the left of the previous value.

24

X

35

= (2 X 3+2 (carry forward) = 8)

Answer: 840

IPM Aptitude Questions & Answers based on Cross Multiplication

Learning simple tricks will not only help manage your time in the final exam but also help you solve the questions with accuracy. You can increase your speed by more than 100% by learning a few simple tricks.

As per experts, solving previous year Question Papers of IPMAT will help you get an idea about the type of questions asked and the difficulty level of questions.

Let us understand how to multiply more significant numbers by using the cross multiplication technique.

Question:Multiply 235 X 275

Step-1: multiply the unit figures, that is, multiply 5 of 235 by 5 of 275 (5 x 5 = 25), put five at the answer figure area, and carry over 2 for the next step.

Step-2: do cross multiplication, that is, multiply 3 and 5 of 235 by 5 and 7 of 275 respectively and add the two products (3 x 5 + 5 x 7 = 15 + 35= 50).

Now, add the number 2 carried from step1 with 50 (50 + 2 = 52), put two on the left side of 5 in the answer figure, and take over 5 for the next step.

Step-3: do three way multiplications. You need to multiply 2, 3 and 5 of 235 by 5, 7 and 2 of 275 respectively and add all the products (2 x 5 + 3 x 7 + 5 x 2 = 10 + 21 + 10 = 41).

Now, add 5 (carried from Step2) with 41 (41 + 5 = 46), put 6 at the left side of 25 in the answer figure, and carry over 4 to the next step.

Step-4: again do cross multiplication. But this time it should be the tenth and hundredth digits of both the numbers. Multiply 2 and 3 of 235 by 7 and 2 of 275 respectively and add the products (2 x 7 + 3 x 2 = 14 + 6 = 20).

Now add 4 (carried from Step3) with 20 (20 + 4 = 24), put 4 at the left side of 625 in the answer figure, and carry over 2 to the next step.

Step-5: It is the final step. Multiply 2 of 235 by 2 of 275 (2 x 2 = 4), add 2 (carried from Step4) with 4, and put it at the left side of 4625 in the answer figure and you will get the final answer 64625.

Question: Multiply 1235 X 275

Step-1: multiply 5 of 1235 with 5 of 275 (5 x 5 = 25), put 5 at the answer figure area and carry over 2 for next step.

Step-2: do cross multiplication, that is, multiply 3 and 5 of 1235 with 5 and 7 of 275 respectively and add the products (3 x 5 + 5 x 7 = 15 + 35 = 50).

Now, add 2 (carried from Step1) with 50 (50 + 2 = 52), put 2 at the left side of 5 in the answer figure and carry over 5 for the next step.

Step-3: Do three way multiplications, that is, you need to multiply 2, 3 and 5 of 1235 with 5, 7 and 2 of 275 respectively and add the products (2 x 5 + 3 x 7 + 5 x 2 = 10 + 21 + 10 = 41).

Now add 5 (carried from Step2) with 41 (41 + 5 = 46), put 6 at the left side of 25 in the answer figure and carry over 4 to the next step.

Step-4:- Again do three way multiplications. But this time you need to multiply 1, 2 and 3 of 1235 with 5, 7 and 2 of 275 respectively and add all the products (1 x 5 + 2 x 7 + 3 x 2 = 5 + 14 + 6 = 25).

Now add 4 (carried from Step3) with 25 (25 + 4 = 29), put 9 at the left side of 625 in the answer figure and carry over 2 for the next step.

Step-5: Now do cross multiplication that consisting 1 and 2 of 1235 with 7 and 2 of 275 respectively and add the products (1 x 7 + 2 x 2 = 7 + 4 = 11).

Now, add 2 (carried from Step4) with 11 (11 + 2 = 13), put 3 at the left side of 9625 in the answer figure and carry over 1 to the next step.

Step-6: this is the final step. Multiply 1 of 1235 with 2 of 275 (1 x 2 = 2) and add 1 (carried from Step5) with 2 (2 + 1 = 3), put 3 at the left side of 39625 and the final answer of the question is 339625.

We've compiled a list of all of the most relevant quantitative aptitude topics in one place. Please take a look at them as well -

Question: How many positive integer divisors of are less than but do not divide ?

Solution:

First we prime factorize n, n = apbqcr.....

No. of factors = (1+p)(1+q)(1+r)....

For example factors of 12 are = 22 x 31, no. of divisors = (2+1)(1+1) = 6.

Number of factors of n = (29 + 1)( 17 +1 ) = 30 x 18

n2 = 258 x 334

Number of factors of n2 = (58 + 1 )(34 +1) = 59 x 35.

No. of factors of n2 that are less than n = (59 x 35 - 1) / 2

(solving 59 x 35 using cross multiplication to save time, 59x 35 = 2065)

Ans: 1032

How to Find Square of any number using Cross Multiplication?

Learning important Maths Formulas will help you solve the questions quickly in the upcoming exam. You can follow the simple technique given below to find the square of any number.

Example:

Finding square of 72 using cross multiplication

72 X 72

Step-1: Multiply the one’s digits of both the numbers and then note the ones digit number of the product in the answer.

Here we need to multiply 2 x 2 which would give us 4 and then noting 4 in the answer.

72

X

72

=4

Step-2: Multiply the diagonals and add them together. In this problem, we have 7 x 2 = 14 and 7 x 2 = 14 as the diagonals. Add the results together to obtain 28 and write its one-digit value down next to 4 and take the tens digit to carry forward.

72

X

72

= ( 2X 7 + 2X 7 = 28 )

84

Step 3: Multiply the digits in the ten’s column together and write the number to the left of the previous value.

72

X

72

=(7 X7+2(carry forward) = 51)

Answer: 5184

FAQ's

What is the best strategy to clear the IPMAT QA Section?

Due to the sectional time limit in the IPMAT exam, QA becomes even harder to score. Therefore, it is important to devote time carefully to each question.

You must choose the questions you want to attempt wisely as it is not possible to attempt all the questions in the given time.

Try to attempt the questions that you are good at first, later move to other questions. This will help you save time and build up your confidence for the rest of the questions.

If you are not able to find the solution for a particular question, do not waste time on it. Instead, move to the next question and come back to it later if time permits.

Use tricks of Vedic maths like cross multiplication to save calculation time during the examination.

How can you increase your IPMAT score in the last few months?

The best method to improve your score in the last few months is to attempt mock tests and apply all the tips and tricks like the one mentioned above in a time-based mock exam. Practicing mock exams will not only help you increase your speed and accuracy on exam day, but it will also help you assess your level of preparation for the exam.

You can also learn about the paper's difficulty level and the kind of questions that will be asked during the exam.

Taking mock examinations will help you improve your time management skills and increase your confidence.

Which is the best online coaching for IPMAT 2021 preparation?

Supergrads is one of the best online coaching institute for IPMAT preparation, they have educated and guided thousands of management aspirants who are now enrolled in prestigious universities. With the main emphasis on bringing out students' true potential in order to improve their performance. They provide Interactive live classes and doubt clearing sections with scheduled mock exams.

Which is the best IPM Study Material for Quantitative Ability?

For cracking the quantitative ability section, refer to R.D.Sharma or R.S.Aggarwal book. It includes all the concepts from the 12th standard explained in depth. It is also easily understandable without any tutor.

What is the rule of cross multiplication?

In the cross multiplication, you have to multiply the numerator of the first fraction with the denominator of the second fraction and the numerator of the second fraction with the denominator of the first fraction.

What is the other name for Cross Multiplication?

Cross Multiplication is also termed as Vedic Multiplication.