Updated On : July 26, 2023

When we converse about the Design Entrance Exam, then we cannot skip talking over aptitude. The Aptitude section has some of the most tricky questions from the very basic area of mathematics. Also, there are positive odds of scoring high in the aptitude section if you make the preparation right. Now you must be guessing about what is right or point preparation. Well in this preparation you stop beating the bush and Focus on the key concepts of each formula and their applications in myriad cases.

This blog is somewhat similar. Here we will earmark our focus on Speed, distance, and time for the design entrance examination. We chose to talk about this topic because many students come across different tricky questions about speed, distance, and time.

However, they always tend to make mistakes because of unclear concepts or because they remain uncertain about their application. There are almost 4-6 questions in the Aptitude section from speed, distance, and time. We have created this blog dedicated to you all so that you can acquire some ideas about the variety of questions you can encounter.

Also, we have solved a few questions for you to eradicate every perplexity about the application of the concept. Hope you will find it exclusively worthwhile.

We have a few solved examples for your reference. Once you go through this section you will be able to understand the basic concepts and applications of speed, distance, and time formulas. Let's have a look at the basic formula first.

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If we take 1km/h then the km stands for distance, Hour stands for time and the (/) slash represents the division. Therefore:

**Speed = Distance/Time**

**Distance = Speed x Time **

**Unit of Speed, distance, and time **

**1km = 1000 m**

**1 hr = 60 min**

Now,

**1km/ hr = 1000/60 min**

And if you want to convert it into seconds then:

**1000/60 x 60**

**= 5/18 m/sec**

Hence:

**1km/h = 5/18 m/sec**

It means that an object has covered 5 meters in 18 sec.

**Read more: Important Aptitude Formulae for Design Entrance Exams**

Ans:

Speed = 180km/h

1 km/sec = 5/18 km/se

180 km/h = 5/18 x 180

= 50m/sec

Ans:

Given Speed = 5m/sec

Time = 2hr 40 mins

= 2 x 60 + 40

= 120+40

=160 mins

Now, multiply 160 by 60 to convert it into seconds.

= 160x60

= 9600 sec

A/Q

1sec = 5m

So in 2hr 40 mins or 9600 sec, the traveled distance is :

= 9600 x 5

= 48000 m

Now Convert

1km = 1000 m

1 m = 1/1000

Then,

**48000 m/ 1000 m**

**= 48 km **

Another Short method to do this question is :

Distance = Speed x time

= 5 x 9600 sec

= 48000 m

**5x9600/1000**

**= 48 km **

**Read more: ****How to prepare Aptitude for Design Exams?**

Ans:

**1hr = 60 km**

**1 hr = 40 km**

**Returning requires 1.5 hours to cover the distance of 60km at a speed of 40km/h.**

**So the Average speed is: **

**Total distance/ Total time**

**60+60/ 1hr + 1.5 hr **

**Distance = d**

**Time = t**

**Speed = 60km/h**

**Time (AB) = d/60**

**Time (BA) = d/40**

**d+d/total time**

**= d/60 + d/40**

**= 2d/ d{1/60 + 1/40}**

**= 2+3/120**

**= 5/120**

**= 48km/h**

Another way is to take the LCM of both the units mentioned in the question. i.e: 60 & 40. Hence,

LCM (40+60) = 2+3/120

120/60 = 2hrs

120/40 = 3 hrs

120+120/2+3 = 240/5

= 48 km

Q: An Aeroplane flies along the four sides of a square at a speed of 200, 400, 600, and 800 km/hr respectively. The speed of the plane around the field in km/hr is?

Q: A student goes to school at the rate of 5/2km per hour from his house and reaches 6 mins late. If he travels at the speed of 3 km/hr he reaches the school 10mins earlier, which is the distance of the school from the house.

Q: A student goes to school at a rate of 3km/ hr from his house and returns at 2km/h. It takes him 10 hrs to travel. Find the distance traveled by him.

Q: Walking 5/6th of his actual speed Mike reached his destination 10 mins late. Find his usual time and time taken on this occasion.

Q: How much time a person will take to cover 300km if he travels at 50km/h and if he takes a break of 5 mins after every 40 km?

Q: Excluding stoppages, the speed of a bus is 54km/h and including stoppages, it is 45 km/h. For how many minutes does the bus stop per hour?

Q: A man goes to the market on foot and returns by bike from the market to home in 35 minutes. If he rides a bike it takes 10 min. How much time does it take if he goes to the market and comes back on foot?

Q: A plane is left 30 minutes later than its usual time and to reach the destination 15000 km away it had to increase its speed by 100km/h from the usual speed. Find the usual speed.

Q: Ratio of speed a,b,c,d is 4:6:8:9. They travel a distance of 236 km. The slowest car takes 144 minutes to reach the distance. How much is the fastest car going to take?

**Read more:** **Best Books for Design Entrance Exams**

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