Download CUET Chemical Kinetics Questions PDF With Answers

Overview: Get access to CUET Chemical Kinetics Questions, including MCQs, PYQs, and a free PDF with detailed solutions. These questions will help you to clear your concepts and improve accuracy so that you can prepare smartly for the CUET exam.

Do you know that many students find chemistry weak while preparing for the CUET UG exam? The main reason is that their basic concepts are not clear. But now, with the help of CUET Chemical Kinetics questions and answers, you can fix this problem easily.

Here you’ll get MCQs, previous year questions, and important problems with detailed solutions. Solving them will make your concepts stronger, improve your speed, and give you the confidence to score better in the CUET exam.

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Download CUET Chemical Kinetics Questions with Solution PDF

If you are preparing for CUET, then chemical kinetics is a very important topic. Many students feel it is hard, but with the right practice, you can score full marks. To help you, we have made a CUET Chemical Kinetics Questions with Solution PDF.

In this PDF, you will find different types of questions like:

• MCQs (Multiple Choice Questions): These help you test your speed and accuracy.
• Practice Questions: Step-by-step questions that improve your basics.
• Previous Year CUET Questions (PYQs): Real exam-level questions for smart practice.

Every question in the CUET Chemical Kinetics Questions PDF comes with a detailed solution. So, if you make a mistake, you can easily check the answer and understand the right method. This makes your preparation strong and saves time during revision.

The PDF also covers important questions and sample questions that can come in the exam. By solving these regularly, you will get more confidence and reduce silly errors.

Download this CUET Chemical Kinetics Questions PDF now and start your exam preparation in the best way. Remember, practicing questions daily will help you to clear all your concepts.

Download CUET Chemical Kinetics Questions & Answer PDF

CUET Chemical Kinetics Questions and Answers

Q1. For the equilibrium, A(g) ⇌ B(g), ΔH is –40 kJ/mol. If the ratio of the activation energies of the forward (Ef) and reverse (Eb) reactions is 2/3, then:

(a) Ef = 60 kJ/mol; Eb = 100 kJ/mol

(b) Ef = 30 kJ/mol; Eb = 70 kJ/mol

(c) Ef = 80 kJ/mol; Eb = 120 kJ/mol

(d) Ef = 70 kJ/mol; Eb = 30 kJ/mol

Answer: (c)

Explanation:

Given: ΔH = Eb – Ef = –40 kJ/mol

And, Ef/Eb = 2/3 → Ef = (2/3)Eb

Substituting:

–40 = Eb – (2/3)Eb → –40 = (1/3)Eb → Eb = 120 kJ/mol

Ef = 2/3 × 120 = 80 kJ/mol

Q2. For the reaction A + 2B → C, rate is given by R = [A][B]². Then the order of the reaction is:

(a) 3

(b) 6

(c) 5

(d) 7

Answer: (a)

Explanation:

Order = exponent of [A] + exponent of [B] = 1 + 2 = 3

Q3. If 50% of a reaction occurs in 100 seconds and 75% of the reaction occurs in 200 seconds, the order of this reaction is:

(a) 1

(b) 2

(c) 0

(d) 3

Answer: (a)

Explanation:

For a first-order reaction,

t₁/₂ = constant (independent of concentration)

50% completion → 1 half-life (100 s)

75% completion → 2 half-lives = 200 s

→ Confirms first-order

Q4. In a first-order reaction, the concentration of the reactant decreases from 0.8 M to 0.4 M in 15 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is:

(a) 30 minutes

(b) 15 minutes

(c) 7.5 minutes

(d) 60 minutes

Answer: (a)

Explanation:

Each half-life halves the concentration

0.1 → 0.05 → 0.025: 2 half-lives

One half-life = 15 min → Total = 30 min

Q5. The rate law for the reaction below is given by the expression: Rate = k[A][B]

A + B → Product

If the concentration of B is increased from 0.1 to 0.3 mole, keeping [A] at 0.1 mole, the rate constant will be:

(a) 3k

(b) 9k

(c) k/3

(d) k

Answer: (d)

Explanation:

k is the rate constant, which depends only on temperature, not concentrations.

So, k remains unchanged.

Q6. A reaction is found to be of second order with respect to concentration of carbon monoxide. If concentration of carbon monoxide is doubled, the rate of reaction will

(a) triple

(b) increase by a factor of 4

(c) double

(d) remain unchanged

Answer: (b) increase by a factor of 4

Explanation:

The rate law expression is R = k[CO]².

When concentration of CO is doubled, the rate law expression becomes

R′ = k[2CO]² = 4k[CO]² = 4R.

Q7. For a chemical reaction, X+2Y→Z, if the rate of appearance of Z=0.50 moles/L per hour, then the rate of disappearance of Y is

(a) 0.5 mol L⁻¹ hr⁻¹

(b) 1.0 mol L⁻¹ min⁻¹

(c) 0.25 mol L⁻¹ hr⁻¹

(d) cannot be predicted

Answer: (b) 1.0 mol L⁻¹ min⁻¹

Explanation:

Rate of disappearance of X = 2 × rate of appearance of Z = 2 × 0.5 = 1.0 mol L⁻¹.

Q8. The rate of a reaction is primarily determined by the slowest step. This step is called

(a) rate-determining step

(b) activation step

(c) reaction rate step

(d) none of these

Answer: (a) rate-determining step

Explanation:

The rate-determining step is a slow step by which the rate of reaction can be determined.

Q9. The reaction of high molecularity are very rare because

(a) Bodies collisions have a low probability. 

(b) Bodies collisions are not favoured energetically.

(c) Activation energy of bodies collisions is very large.

(d) Very high concentration is needed for such reactions.

Answer: (a) Bodies collisions have a low probability.

Explanation:

The reactions of higher order are rare because many body collisions have a very low probability. The chances of three or more molecules colliding at the same time to give product are very low.

Q10. For a chemical reaction A → B, it is observed that the rate of the reaction quadruples when the concentration of A is doubled. So, rate expression for the reaction is, rate = k [A]ⁿ where the value of n is

(a) 1

(b) 2

(c) 0

(d) 3

Answer: (b) 2

Explanation:

Rate = k[A][B] and Rate = k[A]² are both second order reactions. In the first case, A and B are both first order and in the second, A is second order.

If a reactant is second order, then when its concentration is doubled, the rate of the reaction quadruples (2² = 4). If the concentration is tripled, the rate increases by a factor of 9 (3² = 9).

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Features & Benefits of CUET Chemical Kinetics Questions

Chemical Kinetics Questions are very helpful for exam preparation. They give you the right type of practice and build your confidence. Here are the key features and benefits:

• Complete Coverage: The CUET Chemical Kinetics Questions PDF includes all topics from the chapter, so you don’t miss anything important.
• Expert Designed: Made by subject experts, these CUET Chemical Kinetics Sample Questions match the CUET exam level and pattern.
• Better Practice: Solving CUET Chemical Kinetics Practice Questions improves problem-solving skills and helps you handle both easy and tricky questions.
• Detailed Answers: The CUET Chemical Kinetics Questions and Answers PDF provides step-by-step solutions. This improves your understanding and reduces mistakes.
• Simple & Organized: The PDF is well-structured, making last-minute revision easier and faster.
• Score Improvement: Practicing CUET Chemical Kinetics PYQ and CUET Chemical Kinetics Important Questions improves accuracy, memory, and speed. This will help you to score higher marks in the CUET exam.

Overall, CUET Chemical Kinetics Questions for Exam Preparation are the best tool to study smartly, revise quickly, and perform well in CUET.

Preparation Tips for CUET Chemical Kinetics 2026

To score well in CUET, you must prepare smartly for chemical kinetics. Here are some simple and effective tips:

Know the Exam Pattern

Understand how CUET chemical kinetics questions are asked and their weightage.

Cover the Full Syllabus

Revise all topics from NCERT and extra study material.

Daily Practice

Solve CUET Chemical Kinetics PYQ and CUET Chemical Kinetics Practice Questions PDF regularly.

Use Mock Tests

Attempt CUET mock tests and sample papers to test your speed and accuracy.

Focus on Important Questions

Spend extra time on CUET Chemical Kinetics important questions and formulas.

Revise Smartly

Use the CUET Chemical Kinetics Questions and Answers PDF for quick revision before exams.

With regular practice and revision, you can master this topic, build confidence, and score high in the CUET exam.

Overview of Chemistry Exam Pattern 2026

Understanding the CUET 2026 Chemistry exam pattern is crucial if you want to maximize your score and secure admission in top universities. The NTA has already reduced the CUET chemistry syllabus from 16 units to 10 units, which makes preparation more focused.

Chemistry is one of the most opted domain subjects in CUET, with 5.7 lakh+ students appearing in 2025. Since the highest marks touched 247.64/250, even small mistakes can cost you a top rank. Knowing the exam pattern, number of questions, marking scheme, and syllabus weightage will help you prepare smarter.

Particulars	Details
Exam Conducting Body	National Testing Agency (NTA)
Subject	Chemistry (Domain Subject – Section II)
Total Units in Syllabus	10 Units (based on Class 12 NCERT)
Total Questions Asked	50 Questions
Questions to be Attempted	All 50 (compulsory)
Question Type	Objective (MCQ) – Concept, Application & Case-Based
Marking Scheme	+5 for Correct Answer, -1 for Wrong Answer
Maximum Marks	250
Difficulty Level	Moderate (easier than JEE/NEET but highly competitive)
Duration	60 minutes

Key Takeaways

Preparing with the right approach to the CUET 2026 Chemistry exam pattern can help you maximize your score. Since the syllabus is reduced to 10 units, focusing on important chapters, solving PYQs, and practicing case-based questions will give you an edge over others.

• Attempt regular CUET mock tests to analyze your weak areas and improve speed.
• Also, joining the right CUET coaching can provide expert guidance, doubt-solving, and structured preparation.