October 8, 2026
Races and Games Questions for IPMAT are an important part of the Quantitative Ability section. These questions are mainly based on speed, distance, time, speed ratios, winning margins, head starts, and games or tournaments. In recent IPMAT papers, this topic has appeared in different forms, with the number of questions varying each year.
In IPMAT Indore, the Quantitative Ability section has 45 questions, including 30 MCQs and 15 Short Answer Questions. While Races and Games does not have a fixed number of questions, understanding its common patterns can help you solve these questions faster and more accurately.
In this guide, you will find important concepts, formulas, solved examples, and practice questions to strengthen your preparation for Races and Games Questions for IPMAT 2027.
A race is a contest in which two or more people cover a fixed distance, either on a straight course or a circular track. A game is a contest of points, such as a game of 100 points in billiards. Both are tested as applications of speed ratios.
Races and Games vs Games and Tournaments: Don't Mix Them Up
Students often confuse these two topics because both use the word "games".
| Topic | Section | What it tests | Core idea |
|---|---|---|---|
| Races and games (of points) | Quantitative Ability | Speed and scoring ratios | When A scores P, B scores P − x |
| Games and tournaments | Logical Reasoning / DI-LR | Match structures and outcomes | Knockout with n players needs n − 1 matches; a round robin needs n(n − 1) ÷ 2 matches |
This article covers the first. If you are preparing for IPMAT Rohtak's reasoning section or JIPMAT's DILR, also review the IPMAT logical reasoning syllabus.
Question: In a 1 km race, A beats B by 40 m or 8 seconds. How long does A take to finish?
Solution: B covers the last 40 m in 8 seconds, so B's speed = 40 ÷ 8 = 5 m/s. B's time for 1,000 m = 200 seconds. A finishes 8 seconds earlier, so A takes 192 seconds.
Mentor note: The phrase "x m or t seconds" always hands you the loser's speed. Start there.
Question: In a 100 m race, A beats B by 10 m and B beats C by 10 m. By how much does A beat C?
Solution: When A runs 100 m, B runs 90 m. When B runs 100 m, C runs 90 m, so when B runs 90 m, C runs 90 × 0.9 = 81 m. A beats C by 100 − 81 = 19 m.
Mentor note: The tempting answer is 20 m, and it often appears among the options.
Question: A's speed is 5/3 times B's speed. What start should A give B in a 200 m race so that it ends in a dead heat?
Solution: In the time A runs 200 m, B runs 200 × 3/5 = 120 m. B must start 200 − 120 = 80 m ahead.
Pattern 4: Circular Track
Question: A and B start together from the same point on a 600 m circular track at 4 m/s and 6 m/s.
| What is asked | Working | What it tests | Answer |
|---|---|---|---|
| First meeting, same direction | 600 ÷ (6 − 4) | 300 s | |
| First meeting, opposite directions | 600 ÷ (6 + 4) | 60 s | |
| First meeting at the starting point | LCM of lap times 150 s and 100 s | 300 s | |
| Distinct meeting points, same direction | Speed ratio 2 : 3, so 3 − 2 | 1 point | |
| Distinct meeting points, opposite directions | 3 + 2 | 5 points |
Question: In a game of 100 points, A can give B 20 points and C 28 points. How many points can B give C in a game of 90?
Solution: A : B = 100 : 80 and A : C = 100 : 72, so B : C = 80 : 72 = 10 : 9. When B scores 90, C scores 81. B can give C 9 points.
Mentor note: 28 − 20 = 8 is the trap answer. Points scale like metres, so subtraction does not work.
Question: In a 500 m race, A gives B a start of 50 m and still beats B by 25 m. Find the ratio of their speeds.
Solution: When A runs 500 m, B has run 500 − 50 − 25 = 425 m. A : B = 500 : 425 = 20 : 17.
Mentor note: Subtract both the start and the margin from L to get the loser's distance.
Question: A runs 400 m in 80 seconds and B runs it in 100 seconds. How many seconds' start should A give B for a dead heat? What is that start in metres?
Solution: B needs 20 seconds more than A, so B must start 20 seconds earlier. B's speed is 400 ÷ 100 = 4 m/s, so a 20-second start equals 4 × 20 = 80 m.
Mentor note: A time start and a distance start describe the same advantage. Convert using the slower runner's speed.
Attempt each Races and Games question for IPMAT on a timer before opening the hint. Aim for about 60 seconds on Q1–Q4, 90 seconds on Q5–Q8 and 2 minutes on Q9–Q10. Questions run from easy to hard.
SA mode for IPMAT Indore aspirants: cover the options and type your answer first. In the SA section, you cannot back-solve from choices, so practise solving without them.
Q1. (Easy) In a 200 m race, A beats B by 25 m. What is the ratio of A's speed to B's speed?
(a) 7 : 8
(b) 9 : 8
(c) 8 : 7
(d) 25 : 8
Hint: When A runs 200 m, how far has B run?
Answer: (c) 8 : 7
Solution: B runs 175 m while A runs 200 m. Ratio = 200: 175 = 8: 7.
Q2. (Easy) In a 500 m race, A beats B by 50 m or 10 seconds. How long does A take to complete the race?
(a) 80 s
(b) 90 s
(c) 95 s
(d) 100 s
Hint: "50 m or 10 seconds" gives you B's speed directly.
Answer: (b) 90 s
Solution: B's speed = 50 ÷ 10 = 5 m/s. B's time = 500 ÷ 5 = 100 s. A's time = 100 − 10 = 90 s.
Q3. (Easy) A runs 1 km in 3 minutes 10 seconds, and B runs it in 3 minutes 20 seconds. By what distance does A beat B?
(a) 40 m
(b) 55 m
(c) 50 m
(d) 60 m
Hint: Find how far B is from the finish line during the 10 seconds by which A is faster.
Answer: (c) 50 m
Solution: B's speed = 1,000 ÷ 200 = 5 m/s. When A finishes, B still needs 10 seconds, which is 5 × 10 = 50 m.
Q4. (Easy) A and B start from the same point on a 400 m circular track and run in opposite directions at 5 m/s and 3 m/s. After how many seconds do they meet for the first time?
(a) 40 s
(b) 80 s
(c) 50 s
(d) 200 s
Hint: Opposite directions, so add the speeds.
Answer: (c) 50 s
Solution: Time = 400 ÷ (5 + 3) = 50 s. Option (d) 200 s is the same-direction answer.
Q5. (Medium) In a 1 km race, A beats B by 100 m and B beats C by 100 m. By how many metres does A beat C?
(a) 200 m
(b) 180 m
(c) 210 m
(d) 190 m
Hint: Do not add the margins. Find how far C has run when B has run 900 m.
Answer: (d) 190 m
Solution: B : C = 1,000: 900. When B runs 900 m, C runs 900 × 0.9 = 810 m. A beats C by 1,000 − 810 = 190 m.
Q6. (Medium) A runs 5/3 times as fast as B. If A gives B a start of 80 m, how long should the race course be so that both reach the finish line together?
(a) 200 m
(b) 160 m
(c) 240 m
(d) 300 m
Hint: Let the course be L. A runs L while B runs L − 80.
Answer: (a) 200 m
Solution: L ÷ (L − 80) = 5/3, so 3L = 5L − 400 and L = 200 m.
Q7. (Medium) In a game of 100 points, A can give B 20 points and C 32 points. How many points can B give C in a game of 100?
(a) 12
(b) 16
(c) 18
(d) 15
Hint: Write A : B and A : C, then combine to get B : C.
Answer: (d) 15
Solution: B : C = 80 : 68 = 20 : 17. When B scores 100, C scores 85. B gives C 15 points. Option (a) 12 is the subtraction trap.
Q8. (Medium) In a 100 m race, A beats B by 10 m and C by 13 m. In a 180 m race, by how many metres will B beat C?
(a) 6 m
(b) 3 m
(c) 5 m
(d) 7 m
Hint: When A finishes, B and C have run 90 m and 87 m. That is their speed ratio.
Answer: (a) 6 m
Solution: B : C = 90 : 87 = 30 : 29. When B runs 180 m, C runs 174 m. B wins by 6 m.
Q9. (Hard) Two runners start together from the same point on a circular track and run in the same direction with speeds in the ratio 7 : 4. At how many distinct points on the track will they meet?
(a) 11
(b) 3
(c) 4
(d) 7
Hint: Same direction uses the difference of the ratio terms; opposite uses the sum.
Answer: (b) 3
Solution: The ratio 7 : 4 is in lowest terms, so distinct meeting points = 7 − 4 = 3. Option (a) 11 is the opposite-direction answer.
Q10. (Hard) A and B run a 3 km race on a 300 m circular track, starting together and running in the same direction at 7 m/s and 5 m/s. How many times does A overtake B before A finishes the race?
(a) 1
(b) 2
(c) 3
(d) 4
Hint: Each overtake means A has gained one full lap (300 m) on B.
Answer: (b) 2
Solution: A finishes in 3,000 ÷ 7 ≈ 428.6 s. A gains 2 m every second, so an overtake happens every 300 ÷ 2 = 150 s, at 150 s and 300 s. The next would be at 450 s, after A has finished. So A overtakes B twice.
Answer Key
| Q | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Answer | c | b | c | c | d | a | d | a | b | b |
How to read your score: 9–10 correct means this topic is a scoring area, so move on to sectional mocks. 6–8 means re-read the terminology table and redo the questions you missed after two days. 5 or fewer means revise Time, Speed and Distance basics first, then return to this set.
Here are the common terminologies for the Races and games questions for IPMAT that confuse students during the exam:
| Phrase in the question | What it actually means | Relationship you write |
|---|---|---|
| A beats B by x m (race of L m) | When A finishes L m, B has run L − x m | A : B = L : (L − x) |
| A beats B by t seconds | B finishes t seconds after A | B's time − A's time = t |
| A beats B by x m or t seconds | B covers the last x m in t seconds | B's speed = x ÷ t |
| A gives B a start of x m | B starts x m ahead, so B runs L − x m | A runs L while B runs L − x |
| A gives B a start of t seconds | B starts running t seconds before A | B runs for t seconds longer than A. For a dead heat, A's running time = B's running time − t |
| Dead heat | Both finish together | Finishing moments are equal |
| A can give B x points in a game of P | When A scores P, B scores P − x | A : B = P : (P − x) |
Check out the list of formulas that can be helpful to solve the Races and Games questions for IPMAT 2027 exam:
| S.No | Concept | Formula / Rule |
|---|---|---|
| 1 | Core Ratio | If A and B run the same time, distance ratio = speed ratio.Speed of A ÷ Speed of B = L ÷ (L − x) |
| 2 | Loser's Speed from Distance-Time Margin | If B loses by a distance x and the time margin is t: Speed of B = x ÷ t |
| 3 | Chain Rule | If A beats B by x and B beats C by y in a race of length L: Distance covered by C when A finishes = (L − x)(L − y) ÷ L. A's margin over C = L − [(L − x)(L − y) ÷ L]Note: A's margin over C is always less than x + y. |
| 4 | Dead Heat with a Head Start | A is faster and gives B a head start of s metres.For a dead heat:L ÷ (L − s) = Speed of A ÷ Speed of B |
| 5 | Circular Track — First Meeting | Track length = C, speeds are a > b, and both start together from the same point.Same direction:Time = C ÷ (a − b)Opposite directions:Time = C ÷ (a + b) |
| 6 | First Meeting at Starting Point | Time taken = LCM of individual lap times.Individual lap times:C ÷ a and C ÷ b. For fractions: LCM = LCM of numerators ÷ HCF of denominators |
| 7 | Distinct Meeting Points | If runners start together and their speed ratio in lowest terms is p : q:Same direction: p − q distinct meeting points. Opposite directions: p + q distinct meeting points |
| 8 | Games of Points | Treat points like metres.If A gives B b points and C c points in a game of P points:B: C = (P − b) : (P − c) |
How to Solve Races and Games Questions for IPMAT: A 4-Step Method
For a broader method of reading Quant questions under exam pressure, see how to approach IIM IPMAT questions.
Here are the common mistakes that must be avoided while solving the IPMAT questions on Races and games topic:
| Mistake | Why it happens | Fix |
|---|---|---|
| Adding chained margins (10 m + 10 m = 20 m) | Treating margins as fixed distances instead of ratios | Always scale; the second margin applies to a shorter distance |
| Reading "start of 20 m" as "A runs 20 m more" | Confusing who gets the start | The person receiving the start runs less |
| Forgetting to subtract both start and margin | Handling only one adjustment | Loser's distance = L − start − margin |
| Subtracting points in games (32 − 20 = 12) | Games feel like simple scoring | Convert to ratios: (P − b) : (P − c) |
| Using the winner's speed for "x m or t s" | Not visualising the finish line | The last x m is run by the loser |
| Not reducing the speed ratio before counting meeting points | Using 6 : 4 instead of 3 : 2 | Reduce to lowest terms first |
| Mixing minutes and seconds | Rushed unit conversion | Convert everything to metres and seconds at the start |
| Counting the start as a meeting or overtake | Over-counting on circular tracks | The starting moment is not a meeting |
Think in distances, not speeds. Most race questions never need actual speeds in m/s. A distance ratio is faster and leaves less room for error.
Draw a 5-second line diagram. Mark the start, the finish and where the loser stands. Most misreadings disappear once you can see it.
Learn the trap options. MCQ options often include the "added margins" answer and the "opposite direction" answer. If your answer matches the obvious trap, check once more.
Practise with Time and Work. Both topics rely on rate and ratio logic, so practising them together builds speed. Pair this set with our IPMAT time and work questions.
Strengthen the base. If ratios feel slow, work through how to improve your quantitative aptitude skills for IPMAT before attempting mixed sets.
Droppers and Class 12 students who already know TSD can compress this into 3 days by combining Days 1–3. To fit this week into your overall schedule, use the IPMAT study plan.
| Day | Focus | Target |
|---|---|---|
| 1 | Revise Time, Speed and Distance basics and relative speed | 15 basic questions |
| 2 | Terminology table and linear races | Patterns 1, 3, 6 and 7; 15 questions |
| 3 | Chained races and games of points | Patterns 2 and 5; 15 questions |
| 4 | Circular tracks | Pattern 4; 15 questions |
| 5 | This article's 10 MCQs under time, then once more in SA mode | Score 8/10 or more |
| 6 | Mixed set from IPMAT PYPs | Note every error type |
| 7 | Sectional Quant mock | Review the races questions first |
Races and games questions for IPMAT reward clear reading more than heavy calculation. Decode the phrase, write the distance ratio, scale it, and check against the common traps. Use relative speed and LCM for circular tracks, convert time starts into distance using the slower runner's speed, and treat points exactly like metres in games.
Frequently Asked Questions
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