Updated On : June 25, 2024

**Reader's Digest - **Tick! Tick! Tick! Ready to Master Time & Work Questions for Law Entrance Exams with this blog? 🕰️📖

Time and Work is one of the most familiar quantitative aptitude topics asked in the law entrance examinations. This is one of those topics which candidates are familiar with even before they start their preparation.

These Time & Work questions work as litmus tests for your ability to navigate complex scenarios. Your strategic thinking, precision, and collaborative mindset are laid bare through these questions.

Here is a glimpse of the main points that will be discussed in the blog:

*Knowing the Basics of Time & Work Questions:**Understanding the fundamental concepts and formulas that underpin Time and Work problems.**Most Frequently Asked Time & Work Questions for Law Entrance Exams:**A comprehensive overview of the types of Time & Work questions that are commonly featured in these exams, with tips on how to approach them.**Sample Time & Work Questions using relevant examples:**Practical exercises and real-world scenarios to illustrate how Time & Work concepts are applied in the context of law and legal reasoning, helping you grasp these concepts effectively.*

Time & Work questions for Law Entrance Exams require you to navigate scenarios involving the interplay between time, efficiency, and tasks completed.

At its core, Time & Work explores how long it takes to complete a task when different individuals or entities work together or individually. This concept applies to real-life scenarios and is a critical skill for aspiring legal minds to master.

In these scenarios, you will encounter a variety of roles: workers, tasks, and the time it takes to complete those tasks. The relationships can be direct or indirect, often leading to intricate problem-solving.

*For instance, it is crucial to understand how the number of workers affects the time it takes to complete a task. This is where the crux of Time & Work lies - in understanding the nuances of these relationships.*

* Read More*:

Below mentioned are the type of questions which may be asked in the law exams from the time and work topic: -

One of the foundational aspects of Time & Work questions is calculating efficiency. This involves discerning how efficiently an individual can complete a task. Efficiency, often denoted as "E," is the rate at which work is completed. It's a powerful metric that forms the bedrock of various problem-solving scenarios.

**Example Question:** If Emily can review contracts at an efficiency of 0.08 contracts per hour, how many contracts can she review in 5 hours?

**Solution:** To find the number of contracts, we use the formula **Work = Efficiency × Time**, which translates to **Work = 0.08 × 5 = 0.4 contracts**. Thus, Emily can review 0.4 contracts in 5 hours

In this type of question, you'll be tasked with finding the time taken by an individual to complete a specific task. It's a journey into understanding an individual's pace and how swiftly they navigate legal intricacies.

**Example Question:** If Jacob can draft a legal memorandum in 6 hours with an efficiency of 0.12, how long would it take him to draft two legal memoranda?

**Solution:** Using the formula **Time = Work / Efficiency**, we calculate Jacob's time as **Time = 2 / 0.12 = 16.67 hours**. Therefore, it would take Jacob approximately 16.67 hours to draft two legal memoranda.

When legal minds collaborate, their collective efficiency paves the way for dynamic teamwork. Group time calculation questions challenge you to unveil the time it takes for a group of individuals to wrap up a shared task.

**Example Question:** Tom and Lisa, working together, can analyze legal cases at a combined efficiency of 0.15 cases per hour. How long would it take them to analyze 10 legal cases?

**Solution:** Utilizing the formula **Time = Work / Combined Efficiency**, we find that **Time = 10 / 0.15 = 66.67 hours**. Hence, it would take Tom and Lisa approximately 66.67 hours to analyze 10 legal cases.

**Check Out - ****Vocabulary-based CLAT reading comprehension **

This type of question dives into the realm of accomplishment. It focuses on understanding how much work an individual can complete within a certain time frame.

**Example Question:** If Olivia can research case laws for 4 hours at an efficiency of 0.06, how much legal research can she accomplish then?

**Solution:** Employing the formula **Work = Efficiency × Time**, we calculate Olivia's work as **Work = 0.06 × 4 = 0.24 units**. Therefore, Olivia can complete 0.24 units of legal research in 4 hours.

Collaboration often weaves a narrative of remarkable achievements. Group work done questions invites you to explore the cumulative output of a legal team within a defined time span.

**Example Question:** A team of paralegals, each with an efficiency of 0.09, collaborates for 12 hours. What is the total work completed by the team?

**Solution:** Employing the formula **Work = Efficiency × Time**, we calculate the total work as **Work = 0.09 × 12 = 1.08 units**. Thus, the team of paralegals accomplishes a total work of 1.08 units in 12 hours.

Time and work deal with the time taken by an individual or a group of individuals to complete a piece of work and the efficiency of the work done by each of them.

Work to be done is generally considered as one unit, it may be digging a bench, constructing or painting a wall, filling up or emptying a tank, reservoir or a cistern.

Now, below, you will get to know the important information that will help you to solve Time & Work Questions for Law Entrance Exams 2024

- It takes (T) time to complete a certain amount of work (W). The number of units of work done per unit of time is called the rate of work (R).

**Thus, Work (W) = Time (T) x Rate of Work (R).**

- Rate of work and time are inversely proportional to each other.

**Thus, R = 1 / T.**

- If A can do a piece of work in ‘n’ days, then Work done by A in 1 day = 1 / n

For example, If a person can do some work in 12 days, he does 1/12th of the work in one day.

- If A’s 1-day work = 1 / n, then A can finish the whole work in ‘n’ days.

For example, If a person’s one day of work is 1 / 10, then he can finish the whole work in 10 days.

- If A is twice as good as a workman as B, then the ratio of work done by A and B = 2:1, and the ratio of time taken by A and B = 1: 2.

Important Maths Formulas for CLAT 2024

For example, If a man works two times as fast as a woman does, then on completion of the work, two parts of the work have been done by the man and 1 part by the woman.

Also, if they work individually, then the woman takes ten days to complete the work, and the man takes five days to complete the work.

*If two persons, A and B, can individually do some work in ‘a’ and ‘b-days, respectively, then A and B together can complete the same work in ab/a + b-days. {1 / 1 / a + 1 / b = ab / a + b}**If two persons A and B together can complete the same work in ‘a’ days and A (or B) can individually do the same work in b-days, then B (or A) can complete the work in ab / b - a day.*

**Don't Miss - Legal Reasoning Questions for CLAT 2024**

Here is the table of time and work formulae:

Concept | Description |
---|---|

Work Formula | Work = Rate × Time: The fundamental equation that relates work, rate (efficiency), and time. |

Inverse Relationship | As the number of workers increases, the time taken to complete a task decreases, and vice versa. |

Joint Work | When multiple individuals collaborate, their combined rate influences the time taken to complete a task. |

Efficiency | Efficiency dictates the rate at which an individual completes a task, impacting the time required. |

Fractional Work | In scenarios where partial tasks are completed, the work formula reflects the partial completion. |

**Question 1: A can do a piece of work in 10 days, and B can do the same work in 30 days. In how many days can the work be completed if A and B work together?**

(1). 4 5 / 2

(2). 7 1 / 2

(3). 6 9 / 5

(4). 2 3 / 5

(5). None of these

**Explanation:**

To Given: A’s 1 day’s work = 1 / 10

B’s 1 day work = 1 / 30

To Find: How many days can the work be completed if A and B work together?

Solution:

A’s 1 day’s work = 1 / 10

B’s 1 day work = 1 / 30

Therefore,

(A + B)’s 1 day’s work = 1 / 10 + 1 / 30

(A + B)’s 1 day’s work = 2 / 15

Hence, A and B together can do the work in 15 / 2 days, i.e. **7 1 / 2 days.**

**Question 2: A and B together can do a piece of work in 9 days. ‘A’ Alone can complete the work in 12 days. How long will B alone take to complete the job?**

(1). 30 days

(2). 50 days

(3). 60 days

(4). 36 days

(5). 20 days

**Explanation: **

To Given: (A + B)’s 1 day’s work = 1 / 9

A’s Alone 1 day’s work = 1 / 12

To Find: B’s Alone 1 day’s work?

Solution:

(A + B)’s 1 day’s work = 1 / 9

A’s Alone 1 day’s work = 1 / 12

Therefore,

B’s Alone 1 day’s work = 1 / 9 - 1/ 12

B’s Alone 1 day’s work = 1 / 36.

So, B alone can do the work in 36 days.

**Question 3: **A can do work in 25 days. When he had worked for 15 days, B replaced him. If he completes the remaining work in 10 days, in how many days can B alone finish the work?

(1). 20 days

(2). 10 days

(3). 30 days

(4). 40 days

(5). None of these

**Answer: (5) None of these**

**Explanation:**

To given: A’s 1 day’s work = 1 / 25

A’s 15 day’s work = 15 / 25

To find: In how many days can B alone finish the work?

Solution:

A’s 1 day’s work = 1 / 25

A’s 15 day’s work = 15 / 25

A’s 15 day’s work = 3 / 5

Work remaining = (1 - 3 / 5) = 2 / 5 which is done by B in 10 days.

Therefore,

**B can do the work alone in (5 / 2 x 10) = 25 days**

* Read more*:

**Question 4: **A is thrice as good a workman as B and is therefore able to finish a piece of work in 30 days less than B. Find the time in which they can do it working together.

(1). 11 1 / 4

(2). 5 2 / 3

(3). 6 2 / 3

(4). 20 4 / 2

(5). None of these.

**Answer: (1). 11 1 / 4**

**Explanation:**

To given: A is thrice as good as workman as B

To find: the time in which they can do it working together?

Solution:

The ratio of work done by A and B in the same time = 3 : 1

Ratio of time taken by A and B = 1 : 3

Let B takes 𝑥 days to finish a work.

Then,

A takes (𝑥 - 30) days to finish it.

Therefore,

⇒ 𝑥 - 30 / 𝑥 = 1 / 3

⇒ 3𝑥 - 90 = 𝑥

⇒ 𝑥 = 45 days

Thus, A and B can finish the work in 15 days and 45 days, respectively.

Now, (A + B)’s 1 day’s work = 1 / 15 + 1 / 45 = 4 / 45.

**So, both together can finish the work in 45 / 4 days = 11 1 / 4 days.**

Attempt Short Quiz on Time and Work for Law Entrance Exam 2024

**Question 5: **1 woman or 2 men or 3 boys can do a piece of work in 55 days, then the same piece of work will be done by 1 man, 1 woman and 1 boy in how many days?

(1). 18 days

(2). 30 days

(3). 32 days

(4). 16 days

(5). None of these

**Answer: (2) 30 days**

**Explanation:**

To given: 1 woman = 2 man = 3 boys

To find: the same piece of work will be done by 1 man, 1 woman and 1 boy in how many days?

Solution:

1 woman = 2 man = 3 boys

⇒ 1 boy = 2 / 3 man.

⇒ 1 man + 1 woman + 1 boy = 1 man + 2 men + 2 / 3 men

⇒ (1 + 2 + 2 / 3) = 11 / 3 men.

If 2 men can do work in 55 days.

Then,

⇒ 11 / 3 men will do the same work in = 2 x 55 x 3 / 11 = 30 days.

**So, 1 man, 1 woman, and 1 boy will completer the same piece of work in 30 days**

**Question 6: **If 5 men and 2 boys are working together, can do three times as much work per hour as a man and a boy together. The ratio of the work done by a man and that of a boy for a given time is

(1). 1 : 2

(2). 2 : 1

(3). 1 : 3

(4). 3 : 1

(5). None of these

**Answer: (1) 1 : 2**

**Explanation:**

To given: 5 men and 2 boys are working together, and can do three times as much work per hour as a man and a boy together.

To find: ratio of the work done by a man and that of a boy for a given time

Solution:

⇒ 5 men + 2 boy = 3 (1 man + 1 boy)

⇒ 5 men + 2 boy = 3 men + 3 boy

⇒ 2 men = 1 boy

Therefore,

The required ratio of work done by a man and a boy = 1 : 2

**Question 7: **If 2 men and 3 boys can do a piece of work in 16 days and 3 men and 2 boys can do it in 14 days, how long will 5 men and 4 boys take to do it?

(1). 6 days

(2). 8 days

(3). 9 days

(4). 10 days

(5). None of these

**Answer: (2) 8 days**

**Explanation:**

To given: 2 men and 3 boys can do a piece of work in 16 days and 3 men and 2 boys can do it in 14 days.

To find: how long will 5 men and 4 boys take to do it?

Solution:

⇒ 2 men + 3 boys = 16 days

⇒ 2 x 16 men + 3 x 16 boys = 1 day

⇒ 32 men + 48 boys = 1 day …………….. Equation (1)

And

⇒ 3 men + 2 boy = 14 days

⇒ 42 men + 28 boys = 1 day ………….. Equation (2)

On solving Equation (2), we get

⇒ 1 men = 2 boys

⇒ 2 men + 3 boys = 4 boys + 3 boys

⇒ 2 men + 3 boys = 7 boys

And

⇒ 5 men + 4 boys = 10 boys + 4 boys

⇒ 5 men + 4 boys = 14 boys

Now, 7 boys take = 16 days

Therefore,

⇒ 14 boys take = 16 x 7 / 14

** ⇒ 14 boys take = 8 days**

* Read More*:

**Question 8: A and B complete a piece of work in 5 days working together. If A had worked twice, the work would have been completed in 4 days. In how many days can A alone complete the work?**

(1). 20 days

(2). 18 days

(3). 24 days

(4). 15 days

(5). None of these

**Answer: (1). 20 days**

**Explanation:**

Given: A and B complete a piece of work in 5 days working together.

To find: In how many days can A alone complete the work?

Solution:

Let A do the work in ‘a’ days.

A’s 1 day’s work = 1 / a

Let B do the work in ‘b’ days.

B’s 1 day’s work = 1 / b

Now,

⇒ 1 / a + 1 / b = 1 / 5 …………… Equation (1)

⇒ 2 / a + 1 / b = 1 / 4 ……………. Equation (2)

By solving Equation (1) and Equation (2), we get

⇒ a = 20 days.

**Hence, A alone will complete the work in 20 days.**

**Question 9: **If I must hire 6 men and 8 boys for 6 days to do the same piece of work as 8 men and 15 boys could do in 4 days, compare the efficiency ratio of the men and the boys.

(1). 1 : 2

(2). 1 : 3

(3). 1 : 4

(4). 1 : 5

(5). None of these

**Answer: (5). None of these**

**Explanation:**

To given: 6 men + 8 boys can do a piece of work in 6 days

8 men + 15 boys can do a piece of work in 4 days

To find: compare the efficiency ratio of the men and the boys.

Solution:

⇒ (6 men + 8 boys) can do a piece of work in 6 days

⇒ (8 men + 15 boys) can do a piece of work in 4 days

⇒ (6 men + 8 boys) can do a piece of work in 6 days

⇒ (36 men + 48 boys) can do the work in 1 day

⇒ (8 men + 15 boys) can do a piece of work in 4 days

⇒ (32 men + 60 boys) can do the work in 1 day

⇒ 36 men + 48 boys = 32 men + 60 boys

⇒ 36 men - 32 men = 60 boys - 48 boys

⇒ 4 men = 12 boys

⇒ men = 3 boys

**Therefore, the ratio of efficiency of men and boys = 3 : 1.**

**Question 10: **3 men or 5 women can do work in 6 days. How long will 6 men and 5 women take to finish the work?

(1). 2.5 days

(2). 2 days

(3). 3 days

(4). 3.5 days

(5). None of these

**Answer: (2). 2 days**

**Explanation:**

To given: 3 men or 5 women can do work in 6 days

To find: How long will 6 men and 5 women take to finish the work?

Solution:

3 men = 5 women

Or

⇒ 3 x 5 x 6 / (3 x 5 + 6 x 5)

⇒ 3 x 5 x 6 / 45 = 2

⇒ 1 man = 5 / 3 women

⇒ 6 men + 5 women = (6 x 5 / 3 + 5)

⇒ women = 15 women.

Now, if 5 women can do work in 6 days.

⇒ 15 women can do it in (5 x 6 / 15) days = 2 days

**Hence, 6 men and 5 women will take 2 days to finish the work.**

** Question 11: **4 men can do a piece of work in 10 days, 2 women can do it in 15 days and 5 children can do it in 12 days. In how many days can 8 men, 5 women and 15 children together complete the piece of work?

(1). 2 days

(2). 3 days

(3). 4 days

(4). 5 days

(5). None of these

**Answer: (5) None of these**

**Explanation:**

To given: 4 men’s 1 day’s work = 1 / 10.

1 man’s 1 day’s work = 1 / 40.

2 women’s 1 day’s work = 1 / 15.

1 woman’s 1 day’s work = 1 / 30.

5 children’s 1 day’s work = 1 / 12.

1 child’s 1 day’s work = 1 / 60.

To find: In how many days can 8 men, 5 women and 15 children together complete the piece of work?

Solution:

⇒ 4 men’s 1 day’s work = 1 / 10.

⇒ 1 man’s 1 day’s work = 1 / 40.

⇒ 2 women’s 1 day’s work = 1 / 15.

⇒ 1 woman’s 1 day’s work = 1 / 30.

⇒ 5 children’s 1 day’s work = 1 / 12.

⇒ 1 child’s 1 day’s work = 1 / 60.

Now,

⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 8 / 40 + 5 / 30 + 15 / 60

⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 1 / 5 + 1 / 6 + 1 / 4

⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 37 / 60.

**So, they can finish the work in 60 / 37 days.**

**Question 12: **3 men can do a piece of work in 12 days, 5 women in 8 days and 20 children in 3 days. In how many days can a man, a woman, and a child work together to complete the piece of work?

(1). 12 days

(2). 13 days

(3). 14 days

(4). 15 days

(5). None of these

**Answer: (5). None of these**

**Explanation:**

To given: 3 men can do a piece of work in 12 days

5 women can do a piece of work in 8 days.

20 children can do a piece of work in 3 days.

To find: In how many days can a man, a woman, and a child work together to complete the piece of work?

Solution:

⇒ 3 men can do a piece of work in 12 days

⇒ 1 man will do the same piece of work in 36 days.

⇒ 5 women can do a piece of work in 8 days.

⇒ 1 woman will do the same piece of work in 40 days

⇒ 20 children can do a piece of work in 3 days.

⇒ 1 child will do the same piece of work in 60 days.

Now,

⇒ (1 man + 1 woman + 1 child)’s 1 day’s work = 1 / 36 + 1 / 40 + 1 / 60

⇒ (1 man + 1 woman + 1 child)’s 1 day’s work = 5 / 72.

**So, the work is complete in 72 / 5 days = 14 2 / 5 days**

**Question 13: **A certain number of men can complete a piece of work in 40 days. If there were 8 men more the work could be finished in 10 days less. How many men were there afterwards?

(1). 32 men

(2). 28 men

(3). 24 men

(4). 15 men

(5). None of these

**Answer: (1). 32 men**

**Explanation:**

Let the number of men be 𝑥.

𝑥 men can do a work in 40 days.

(𝑥 + 8) men can do the same work in (40 - 10) = 30 days.

⇒ 𝑥 x 40 = 30 (𝑥 + 8)

⇒ 40𝑥 = 30𝑥 + 240

⇒ 40𝑥 - 30𝑥 = 240

⇒ 10𝑥 = 240

⇒ 𝑥 = 24.

Therefore,

**The number of men afterwards = 24 + 8 = 32 men**

**Question 14: **If A can d0 ¼ of the work in 4 days and B can do ⅛ of the work in 3 days, how much will A get if both work together and are paid Rs. 4,500 in all?

(1). Rs. 1,800

(2). Rs. 2,400

(3). Rs. 2,700

(4). Rs. 2,900

(5). None of these

**Answer: (3). Rs. 2,700**

**Explanation:**

Whole work is done by A in (4 x 4) days = 16 days

Whole work is done by Bin (8 x 3) days = 24 days.

A’s wages : B’s wages

⇒ A’s 1 day’s work : B’s 1 day's work

⇒ 1/16 : 1/24

⇒ 3 : 2

Therefore,

⇒ A’s sheet = (⅗ x 4,500)

**⇒ A’s sheet = Rs. 2,700.**

**Question 15: **6 men can complete a piece of work in 12 days. 8 women can do the same piece of work in 18 days whereas 18 children can complete it in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day, how many men would be required totally?

(1). 36 men

(2). 24 men

(3). 18 men

(4). Cannot be determined

(5). None of these

**Answer: (1). 36 men**

**Explanation:**

⇒ (6 x 12) men = (8 x 18) women = (18 x 10) children.

⇒ 2 men = 4 women = 5 children

Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 men

⇒ 6 men’s 1 day’s work = 1/12

⇒ 18 men’s 1 day’s work = 1/12 x 18/6 = ¼

⇒ 18 men’s 2 day’s work = ¼ x 2

⇒ 18 men’s 2 day’s work = ½

Therefore,

The remaining work = 1 - ½

⇒ remaining work = ½

Remaining work can be complete by 18 men in 2 days

**Therefore, to complete in 1 day, men required = 2 x 18 = 36 men**

In conclusion, Time & Work questions are a crucial component of Law Entrance Exams in 2024, demanding candidates' logical reasoning and time management skills.

A thorough understanding of these concepts is paramount to excel in the exams. You must practice extensively to tackle various scenarios and complexities that may arise in the questions.

The key takeaways for success in Time & Work questions for Law Entrance Exams include:

*Mastering fundamental concepts of time, work, and efficiency.**Utilizing efficient problem-solving techniques to save time.**Practicing a diverse range of problems to enhance versatility.**Paying attention to details and avoiding common mistakes.**Managing time effectively during the actual exam.*

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Frequently Asked Questions

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What are the key concepts of Time & Work covered in the 2024 Law Entrance Exams?

What is the average time allocated to solve each Time & Work question in the exam?

How have Time & Work questions evolved over the past years in Law Entrance Exams?

How do the Time & Work questions test a candidate's suitability for law studies?

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What strategies are recommended for tackling Time & Work questions efficiently?

June 25, 2024

**Reader's Digest - **Tick! Tick! Tick! Ready to Master Time & Work Questions for Law Entrance Exams with this blog? 🕰️📖

Time and Work is one of the most familiar quantitative aptitude topics asked in the law entrance examinations. This is one of those topics which candidates are familiar with even before they start their preparation.

These Time & Work questions work as litmus tests for your ability to navigate complex scenarios. Your strategic thinking, precision, and collaborative mindset are laid bare through these questions.

Here is a glimpse of the main points that will be discussed in the blog:

*Knowing the Basics of Time & Work Questions:**Understanding the fundamental concepts and formulas that underpin Time and Work problems.**Most Frequently Asked Time & Work Questions for Law Entrance Exams:**A comprehensive overview of the types of Time & Work questions that are commonly featured in these exams, with tips on how to approach them.**Sample Time & Work Questions using relevant examples:**Practical exercises and real-world scenarios to illustrate how Time & Work concepts are applied in the context of law and legal reasoning, helping you grasp these concepts effectively.*

Time & Work questions for Law Entrance Exams require you to navigate scenarios involving the interplay between time, efficiency, and tasks completed.

At its core, Time & Work explores how long it takes to complete a task when different individuals or entities work together or individually. This concept applies to real-life scenarios and is a critical skill for aspiring legal minds to master.

In these scenarios, you will encounter a variety of roles: workers, tasks, and the time it takes to complete those tasks. The relationships can be direct or indirect, often leading to intricate problem-solving.

*For instance, it is crucial to understand how the number of workers affects the time it takes to complete a task. This is where the crux of Time & Work lies - in understanding the nuances of these relationships.*

* Read More*:

Below mentioned are the type of questions which may be asked in the law exams from the time and work topic: -

One of the foundational aspects of Time & Work questions is calculating efficiency. This involves discerning how efficiently an individual can complete a task. Efficiency, often denoted as "E," is the rate at which work is completed. It's a powerful metric that forms the bedrock of various problem-solving scenarios.

**Example Question:** If Emily can review contracts at an efficiency of 0.08 contracts per hour, how many contracts can she review in 5 hours?

**Solution:** To find the number of contracts, we use the formula **Work = Efficiency × Time**, which translates to **Work = 0.08 × 5 = 0.4 contracts**. Thus, Emily can review 0.4 contracts in 5 hours

In this type of question, you'll be tasked with finding the time taken by an individual to complete a specific task. It's a journey into understanding an individual's pace and how swiftly they navigate legal intricacies.

**Example Question:** If Jacob can draft a legal memorandum in 6 hours with an efficiency of 0.12, how long would it take him to draft two legal memoranda?

**Solution:** Using the formula **Time = Work / Efficiency**, we calculate Jacob's time as **Time = 2 / 0.12 = 16.67 hours**. Therefore, it would take Jacob approximately 16.67 hours to draft two legal memoranda.

When legal minds collaborate, their collective efficiency paves the way for dynamic teamwork. Group time calculation questions challenge you to unveil the time it takes for a group of individuals to wrap up a shared task.

**Example Question:** Tom and Lisa, working together, can analyze legal cases at a combined efficiency of 0.15 cases per hour. How long would it take them to analyze 10 legal cases?

**Solution:** Utilizing the formula **Time = Work / Combined Efficiency**, we find that **Time = 10 / 0.15 = 66.67 hours**. Hence, it would take Tom and Lisa approximately 66.67 hours to analyze 10 legal cases.

**Check Out - ****Vocabulary-based CLAT reading comprehension **

This type of question dives into the realm of accomplishment. It focuses on understanding how much work an individual can complete within a certain time frame.

**Example Question:** If Olivia can research case laws for 4 hours at an efficiency of 0.06, how much legal research can she accomplish then?

**Solution:** Employing the formula **Work = Efficiency × Time**, we calculate Olivia's work as **Work = 0.06 × 4 = 0.24 units**. Therefore, Olivia can complete 0.24 units of legal research in 4 hours.

Collaboration often weaves a narrative of remarkable achievements. Group work done questions invites you to explore the cumulative output of a legal team within a defined time span.

**Example Question:** A team of paralegals, each with an efficiency of 0.09, collaborates for 12 hours. What is the total work completed by the team?

**Solution:** Employing the formula **Work = Efficiency × Time**, we calculate the total work as **Work = 0.09 × 12 = 1.08 units**. Thus, the team of paralegals accomplishes a total work of 1.08 units in 12 hours.

Time and work deal with the time taken by an individual or a group of individuals to complete a piece of work and the efficiency of the work done by each of them.

Work to be done is generally considered as one unit, it may be digging a bench, constructing or painting a wall, filling up or emptying a tank, reservoir or a cistern.

Now, below, you will get to know the important information that will help you to solve Time & Work Questions for Law Entrance Exams 2024

- It takes (T) time to complete a certain amount of work (W). The number of units of work done per unit of time is called the rate of work (R).

**Thus, Work (W) = Time (T) x Rate of Work (R).**

- Rate of work and time are inversely proportional to each other.

**Thus, R = 1 / T.**

- If A can do a piece of work in ‘n’ days, then Work done by A in 1 day = 1 / n

For example, If a person can do some work in 12 days, he does 1/12th of the work in one day.

- If A’s 1-day work = 1 / n, then A can finish the whole work in ‘n’ days.

For example, If a person’s one day of work is 1 / 10, then he can finish the whole work in 10 days.

- If A is twice as good as a workman as B, then the ratio of work done by A and B = 2:1, and the ratio of time taken by A and B = 1: 2.

Important Maths Formulas for CLAT 2024

For example, If a man works two times as fast as a woman does, then on completion of the work, two parts of the work have been done by the man and 1 part by the woman.

Also, if they work individually, then the woman takes ten days to complete the work, and the man takes five days to complete the work.

*If two persons, A and B, can individually do some work in ‘a’ and ‘b-days, respectively, then A and B together can complete the same work in ab/a + b-days. {1 / 1 / a + 1 / b = ab / a + b}**If two persons A and B together can complete the same work in ‘a’ days and A (or B) can individually do the same work in b-days, then B (or A) can complete the work in ab / b - a day.*

**Don't Miss - Legal Reasoning Questions for CLAT 2024**

Here is the table of time and work formulae:

Concept | Description |
---|---|

Work Formula | Work = Rate × Time: The fundamental equation that relates work, rate (efficiency), and time. |

Inverse Relationship | As the number of workers increases, the time taken to complete a task decreases, and vice versa. |

Joint Work | When multiple individuals collaborate, their combined rate influences the time taken to complete a task. |

Efficiency | Efficiency dictates the rate at which an individual completes a task, impacting the time required. |

Fractional Work | In scenarios where partial tasks are completed, the work formula reflects the partial completion. |

**Question 1: A can do a piece of work in 10 days, and B can do the same work in 30 days. In how many days can the work be completed if A and B work together?**

(1). 4 5 / 2

(2). 7 1 / 2

(3). 6 9 / 5

(4). 2 3 / 5

(5). None of these

**Explanation:**

To Given: A’s 1 day’s work = 1 / 10

B’s 1 day work = 1 / 30

To Find: How many days can the work be completed if A and B work together?

Solution:

A’s 1 day’s work = 1 / 10

B’s 1 day work = 1 / 30

Therefore,

(A + B)’s 1 day’s work = 1 / 10 + 1 / 30

(A + B)’s 1 day’s work = 2 / 15

Hence, A and B together can do the work in 15 / 2 days, i.e. **7 1 / 2 days.**

**Question 2: A and B together can do a piece of work in 9 days. ‘A’ Alone can complete the work in 12 days. How long will B alone take to complete the job?**

(1). 30 days

(2). 50 days

(3). 60 days

(4). 36 days

(5). 20 days

**Explanation: **

To Given: (A + B)’s 1 day’s work = 1 / 9

A’s Alone 1 day’s work = 1 / 12

To Find: B’s Alone 1 day’s work?

Solution:

(A + B)’s 1 day’s work = 1 / 9

A’s Alone 1 day’s work = 1 / 12

Therefore,

B’s Alone 1 day’s work = 1 / 9 - 1/ 12

B’s Alone 1 day’s work = 1 / 36.

So, B alone can do the work in 36 days.

**Question 3: **A can do work in 25 days. When he had worked for 15 days, B replaced him. If he completes the remaining work in 10 days, in how many days can B alone finish the work?

(1). 20 days

(2). 10 days

(3). 30 days

(4). 40 days

(5). None of these

**Answer: (5) None of these**

**Explanation:**

To given: A’s 1 day’s work = 1 / 25

A’s 15 day’s work = 15 / 25

To find: In how many days can B alone finish the work?

Solution:

A’s 1 day’s work = 1 / 25

A’s 15 day’s work = 15 / 25

A’s 15 day’s work = 3 / 5

Work remaining = (1 - 3 / 5) = 2 / 5 which is done by B in 10 days.

Therefore,

**B can do the work alone in (5 / 2 x 10) = 25 days**

* Read more*:

**Question 4: **A is thrice as good a workman as B and is therefore able to finish a piece of work in 30 days less than B. Find the time in which they can do it working together.

(1). 11 1 / 4

(2). 5 2 / 3

(3). 6 2 / 3

(4). 20 4 / 2

(5). None of these.

**Answer: (1). 11 1 / 4**

**Explanation:**

To given: A is thrice as good as workman as B

To find: the time in which they can do it working together?

Solution:

The ratio of work done by A and B in the same time = 3 : 1

Ratio of time taken by A and B = 1 : 3

Let B takes 𝑥 days to finish a work.

Then,

A takes (𝑥 - 30) days to finish it.

Therefore,

⇒ 𝑥 - 30 / 𝑥 = 1 / 3

⇒ 3𝑥 - 90 = 𝑥

⇒ 𝑥 = 45 days

Thus, A and B can finish the work in 15 days and 45 days, respectively.

Now, (A + B)’s 1 day’s work = 1 / 15 + 1 / 45 = 4 / 45.

**So, both together can finish the work in 45 / 4 days = 11 1 / 4 days.**

Attempt Short Quiz on Time and Work for Law Entrance Exam 2024

**Question 5: **1 woman or 2 men or 3 boys can do a piece of work in 55 days, then the same piece of work will be done by 1 man, 1 woman and 1 boy in how many days?

(1). 18 days

(2). 30 days

(3). 32 days

(4). 16 days

(5). None of these

**Answer: (2) 30 days**

**Explanation:**

To given: 1 woman = 2 man = 3 boys

To find: the same piece of work will be done by 1 man, 1 woman and 1 boy in how many days?

Solution:

1 woman = 2 man = 3 boys

⇒ 1 boy = 2 / 3 man.

⇒ 1 man + 1 woman + 1 boy = 1 man + 2 men + 2 / 3 men

⇒ (1 + 2 + 2 / 3) = 11 / 3 men.

If 2 men can do work in 55 days.

Then,

⇒ 11 / 3 men will do the same work in = 2 x 55 x 3 / 11 = 30 days.

**So, 1 man, 1 woman, and 1 boy will completer the same piece of work in 30 days**

**Question 6: **If 5 men and 2 boys are working together, can do three times as much work per hour as a man and a boy together. The ratio of the work done by a man and that of a boy for a given time is

(1). 1 : 2

(2). 2 : 1

(3). 1 : 3

(4). 3 : 1

(5). None of these

**Answer: (1) 1 : 2**

**Explanation:**

To given: 5 men and 2 boys are working together, and can do three times as much work per hour as a man and a boy together.

To find: ratio of the work done by a man and that of a boy for a given time

Solution:

⇒ 5 men + 2 boy = 3 (1 man + 1 boy)

⇒ 5 men + 2 boy = 3 men + 3 boy

⇒ 2 men = 1 boy

Therefore,

The required ratio of work done by a man and a boy = 1 : 2

**Question 7: **If 2 men and 3 boys can do a piece of work in 16 days and 3 men and 2 boys can do it in 14 days, how long will 5 men and 4 boys take to do it?

(1). 6 days

(2). 8 days

(3). 9 days

(4). 10 days

(5). None of these

**Answer: (2) 8 days**

**Explanation:**

To given: 2 men and 3 boys can do a piece of work in 16 days and 3 men and 2 boys can do it in 14 days.

To find: how long will 5 men and 4 boys take to do it?

Solution:

⇒ 2 men + 3 boys = 16 days

⇒ 2 x 16 men + 3 x 16 boys = 1 day

⇒ 32 men + 48 boys = 1 day …………….. Equation (1)

And

⇒ 3 men + 2 boy = 14 days

⇒ 42 men + 28 boys = 1 day ………….. Equation (2)

On solving Equation (2), we get

⇒ 1 men = 2 boys

⇒ 2 men + 3 boys = 4 boys + 3 boys

⇒ 2 men + 3 boys = 7 boys

And

⇒ 5 men + 4 boys = 10 boys + 4 boys

⇒ 5 men + 4 boys = 14 boys

Now, 7 boys take = 16 days

Therefore,

⇒ 14 boys take = 16 x 7 / 14

** ⇒ 14 boys take = 8 days**

* Read More*:

**Question 8: A and B complete a piece of work in 5 days working together. If A had worked twice, the work would have been completed in 4 days. In how many days can A alone complete the work?**

(1). 20 days

(2). 18 days

(3). 24 days

(4). 15 days

(5). None of these

**Answer: (1). 20 days**

**Explanation:**

Given: A and B complete a piece of work in 5 days working together.

To find: In how many days can A alone complete the work?

Solution:

Let A do the work in ‘a’ days.

A’s 1 day’s work = 1 / a

Let B do the work in ‘b’ days.

B’s 1 day’s work = 1 / b

Now,

⇒ 1 / a + 1 / b = 1 / 5 …………… Equation (1)

⇒ 2 / a + 1 / b = 1 / 4 ……………. Equation (2)

By solving Equation (1) and Equation (2), we get

⇒ a = 20 days.

**Hence, A alone will complete the work in 20 days.**

**Question 9: **If I must hire 6 men and 8 boys for 6 days to do the same piece of work as 8 men and 15 boys could do in 4 days, compare the efficiency ratio of the men and the boys.

(1). 1 : 2

(2). 1 : 3

(3). 1 : 4

(4). 1 : 5

(5). None of these

**Answer: (5). None of these**

**Explanation:**

To given: 6 men + 8 boys can do a piece of work in 6 days

8 men + 15 boys can do a piece of work in 4 days

To find: compare the efficiency ratio of the men and the boys.

Solution:

⇒ (6 men + 8 boys) can do a piece of work in 6 days

⇒ (8 men + 15 boys) can do a piece of work in 4 days

⇒ (6 men + 8 boys) can do a piece of work in 6 days

⇒ (36 men + 48 boys) can do the work in 1 day

⇒ (8 men + 15 boys) can do a piece of work in 4 days

⇒ (32 men + 60 boys) can do the work in 1 day

⇒ 36 men + 48 boys = 32 men + 60 boys

⇒ 36 men - 32 men = 60 boys - 48 boys

⇒ 4 men = 12 boys

⇒ men = 3 boys

**Therefore, the ratio of efficiency of men and boys = 3 : 1.**

**Question 10: **3 men or 5 women can do work in 6 days. How long will 6 men and 5 women take to finish the work?

(1). 2.5 days

(2). 2 days

(3). 3 days

(4). 3.5 days

(5). None of these

**Answer: (2). 2 days**

**Explanation:**

To given: 3 men or 5 women can do work in 6 days

To find: How long will 6 men and 5 women take to finish the work?

Solution:

3 men = 5 women

Or

⇒ 3 x 5 x 6 / (3 x 5 + 6 x 5)

⇒ 3 x 5 x 6 / 45 = 2

⇒ 1 man = 5 / 3 women

⇒ 6 men + 5 women = (6 x 5 / 3 + 5)

⇒ women = 15 women.

Now, if 5 women can do work in 6 days.

⇒ 15 women can do it in (5 x 6 / 15) days = 2 days

**Hence, 6 men and 5 women will take 2 days to finish the work.**

** Question 11: **4 men can do a piece of work in 10 days, 2 women can do it in 15 days and 5 children can do it in 12 days. In how many days can 8 men, 5 women and 15 children together complete the piece of work?

(1). 2 days

(2). 3 days

(3). 4 days

(4). 5 days

(5). None of these

**Answer: (5) None of these**

**Explanation:**

To given: 4 men’s 1 day’s work = 1 / 10.

1 man’s 1 day’s work = 1 / 40.

2 women’s 1 day’s work = 1 / 15.

1 woman’s 1 day’s work = 1 / 30.

5 children’s 1 day’s work = 1 / 12.

1 child’s 1 day’s work = 1 / 60.

To find: In how many days can 8 men, 5 women and 15 children together complete the piece of work?

Solution:

⇒ 4 men’s 1 day’s work = 1 / 10.

⇒ 1 man’s 1 day’s work = 1 / 40.

⇒ 2 women’s 1 day’s work = 1 / 15.

⇒ 1 woman’s 1 day’s work = 1 / 30.

⇒ 5 children’s 1 day’s work = 1 / 12.

⇒ 1 child’s 1 day’s work = 1 / 60.

Now,

⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 8 / 40 + 5 / 30 + 15 / 60

⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 1 / 5 + 1 / 6 + 1 / 4

⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 37 / 60.

**So, they can finish the work in 60 / 37 days.**

**Question 12: **3 men can do a piece of work in 12 days, 5 women in 8 days and 20 children in 3 days. In how many days can a man, a woman, and a child work together to complete the piece of work?

(1). 12 days

(2). 13 days

(3). 14 days

(4). 15 days

(5). None of these

**Answer: (5). None of these**

**Explanation:**

To given: 3 men can do a piece of work in 12 days

5 women can do a piece of work in 8 days.

20 children can do a piece of work in 3 days.

To find: In how many days can a man, a woman, and a child work together to complete the piece of work?

Solution:

⇒ 3 men can do a piece of work in 12 days

⇒ 1 man will do the same piece of work in 36 days.

⇒ 5 women can do a piece of work in 8 days.

⇒ 1 woman will do the same piece of work in 40 days

⇒ 20 children can do a piece of work in 3 days.

⇒ 1 child will do the same piece of work in 60 days.

Now,

⇒ (1 man + 1 woman + 1 child)’s 1 day’s work = 1 / 36 + 1 / 40 + 1 / 60

⇒ (1 man + 1 woman + 1 child)’s 1 day’s work = 5 / 72.

**So, the work is complete in 72 / 5 days = 14 2 / 5 days**

**Question 13: **A certain number of men can complete a piece of work in 40 days. If there were 8 men more the work could be finished in 10 days less. How many men were there afterwards?

(1). 32 men

(2). 28 men

(3). 24 men

(4). 15 men

(5). None of these

**Answer: (1). 32 men**

**Explanation:**

Let the number of men be 𝑥.

𝑥 men can do a work in 40 days.

(𝑥 + 8) men can do the same work in (40 - 10) = 30 days.

⇒ 𝑥 x 40 = 30 (𝑥 + 8)

⇒ 40𝑥 = 30𝑥 + 240

⇒ 40𝑥 - 30𝑥 = 240

⇒ 10𝑥 = 240

⇒ 𝑥 = 24.

Therefore,

**The number of men afterwards = 24 + 8 = 32 men**

**Question 14: **If A can d0 ¼ of the work in 4 days and B can do ⅛ of the work in 3 days, how much will A get if both work together and are paid Rs. 4,500 in all?

(1). Rs. 1,800

(2). Rs. 2,400

(3). Rs. 2,700

(4). Rs. 2,900

(5). None of these

**Answer: (3). Rs. 2,700**

**Explanation:**

Whole work is done by A in (4 x 4) days = 16 days

Whole work is done by Bin (8 x 3) days = 24 days.

A’s wages : B’s wages

⇒ A’s 1 day’s work : B’s 1 day's work

⇒ 1/16 : 1/24

⇒ 3 : 2

Therefore,

⇒ A’s sheet = (⅗ x 4,500)

**⇒ A’s sheet = Rs. 2,700.**

**Question 15: **6 men can complete a piece of work in 12 days. 8 women can do the same piece of work in 18 days whereas 18 children can complete it in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day, how many men would be required totally?

(1). 36 men

(2). 24 men

(3). 18 men

(4). Cannot be determined

(5). None of these

**Answer: (1). 36 men**

**Explanation:**

⇒ (6 x 12) men = (8 x 18) women = (18 x 10) children.

⇒ 2 men = 4 women = 5 children

Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 men

⇒ 6 men’s 1 day’s work = 1/12

⇒ 18 men’s 1 day’s work = 1/12 x 18/6 = ¼

⇒ 18 men’s 2 day’s work = ¼ x 2

⇒ 18 men’s 2 day’s work = ½

Therefore,

The remaining work = 1 - ½

⇒ remaining work = ½

Remaining work can be complete by 18 men in 2 days

**Therefore, to complete in 1 day, men required = 2 x 18 = 36 men**

In conclusion, Time & Work questions are a crucial component of Law Entrance Exams in 2024, demanding candidates' logical reasoning and time management skills.

A thorough understanding of these concepts is paramount to excel in the exams. You must practice extensively to tackle various scenarios and complexities that may arise in the questions.

The key takeaways for success in Time & Work questions for Law Entrance Exams include:

*Mastering fundamental concepts of time, work, and efficiency.**Utilizing efficient problem-solving techniques to save time.**Practicing a diverse range of problems to enhance versatility.**Paying attention to details and avoiding common mistakes.**Managing time effectively during the actual exam.*

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