October 29, 2025
Overview: Are you ready to tackle IPMAT Trigonometry Questions 2026 like a pro? These questions are a staple in the Quantitative section and can really help you score high if approached correctly.
If you're preparing for the IPMAT 2026 exam, one topic you simply can't afford to skip is Trigonometry.
Every year, the IPMAT Trigonometry Questions section forms a crucial part of the Quantitative Aptitude paper.
Students often fear this topic because of the formulas, ratios, and geometry involved - but once you understand the logic behind it, it becomes one of the easiest and most scoring areas in the entire IPMAT syllabus.
In this detailed guide, we'll break down everything you need to know about IPMAT Trigonometry Questions 2026 - concepts, formulas, problem types, previous year trends, shortcuts, and smart strategies to solve them fast.
Table of Contents
Q1. A kite is flying with a thread 150 meters long. If the thread makes an angle of 60° with the horizontal, find the height of the kite from the ground.
Options:
(a) 50 m
(b) 25√3 m
(c) 75√3 m
(d) 80 m
✅ Answer: (c) 75√3 m
Explanation: Height = 150 × sin(60°) = 150 × (√3/2) = 75√3 m
Q2. A vertical post 15 ft high is broken at a certain height, and its upper part touches the ground making an angle of 30° with it. Find the height at which the post is broken.
Options:
(a) 5 ft
(b) 10 ft
(c) 5√3 ft
(d) 10√3 ft
✅ Answer: (a) 5 ft
Explanation: Total length = 3x = 15 → x = 5 ft → broken at 5 ft height.
Q3. A man observes the top of a tower at an elevation of 30°. After walking some distance towards the tower, the angle becomes 60°. If the tower's height is 30 m, find the distance he moved.
Options:
(a) 22 m
(b) 20 m
(c) 22√3 m
(d) 20√3 m
✅ Answer: (d) 20√3 m
Explanation: Using tan(θ), distance moved = 20√3 m
Q4. The angle of elevation of an airplane from a point on the ground is 60°. After 15 seconds, it becomes 30°. If the airplane is flying at a height of 1500√3 m, find its speed.
Options:
(a) 300 m/s
(b) 100 m/s
(c) 200 m/s
(d) 150 m/s
✅ Answer: (c) 200 m/s
Explanation: Distance covered = 3000 m in 15 sec → Speed = 200 m/s
Q5. Two vertical pillars of heights 16 m and 9 m stand on level ground at a distance of x m apart. If the angles of elevation of their tops from the bottoms of the other are complementary, find x.
Options:
(a) 15 m
(b) 12 m
(c) 16 m
(d) 9 m
✅ Answer: (b) 12 m
Explanation: tan θ × cot θ = 1 → (16/x)(9/x) = 1 → x² = 144 → x = 12 m
Q6. Two vertical posts stand on opposite sides of a road. One post is 108 m high. From the top of this post, the angles of depression of the top and the foot of the other post are 30° and 60°, respectively. Find the height of the other post.
Options:
(a) 36 m
(b) 108 m
(c) 72 m
(d) 110 m
✅ Answer: (c) 72 m
Explanation: Height difference = 108 - 36 = 72 m
Q7. The angle of elevation of the top of a tower from a point 60 m away from its foot is 45°. Find the height of the tower.
Options:
(a) 30 m
(b) 45 m
(c) 60 m
(d) 90 m
✅ Answer: (c) 60 m
Explanation: tan(45°) = h / 60 → h = 60 × 1 = 60 m
Q8. From the top of a lighthouse 100 m high, the angle of depression of a ship is 30°. Find the distance of the ship from the foot of the lighthouse.
Options:
(a) 100√3 m
(b) 150 m
(c) 200√3 m
(d) 300 m
✅ Answer: (a) 100√3 m
Explanation: tan(30°) = 100 / d → d = 100 / (1/√3) = 100√3 m
Q9. The shadow of a tower is √3 times the height of the tower. Find the angle of elevation of the sun.
Options:
(a) 30°
(b) 45°
(c) 60°
(d) 90°
✅ Answer: (a) 30°
Explanation: tan(θ) = height / shadow = 1 / √3 → θ = 30°
Q10. The angle of elevation of the top of a building from a point on the ground is 45°. After moving 20 m closer, the angle becomes 60°. Find the height of the building.
Options:
(a) 20 m
(b) 30√3 m
(c) 20√3 m
(d) 40 m
✅ Answer: (c) 20√3 m
Explanation: Using tan(45°) = h/x and tan(60°) = h/(x−20), solving gives h = 20√3 m
Q11. A man standing on a tower observes a car moving directly towards him. The angle of depression changes from 30° to 60° in 5 minutes. If the height of the tower is 150 m, find the speed of the car.
Options:
(a) 25√3 m/s
(b) 10 m/s
(c) 5√3 m/s
(d) 15 m/s
✅ Answer: (b) 10 m/s
Explanation: tan(30°) = 150 / x₁ → x₁ = 150√3 tan(60°) = 150 / x₂ → x₂ = 150 / √3 Distance covered = 150√3 − 150/√3 = 200√3 m Speed = (200√3) / (5 × 60) = 10 m/s
Q12. From the top of a 50 m tower, the angle of depression of a car on the ground is 60°. Find the distance of the car from the foot of the tower.
Options:
(a) 25 m
(b) 50√3 m
(c) 50/√3 m
(d) 100 m
✅ Answer: (c) 50/√3 m
Explanation: tan(60°) = 50 / x → x = 50 / √3 m
Q13. The top of a 20 m high building is observed at an elevation of 30° from a point A on the ground. Find how far A is from the building.
Options:
(a) 10√3 m
(b) 20√3 m
(c) 15√3 m
(d) 30√3 m
✅ Answer: (b) 20√3 m
Explanation: tan(30°) = 20 / x → x = 20√3 m
Q14. A man is watching a balloon moving vertically upwards. The angle of elevation changes from 30° to 60° as the balloon rises 60 m. Find the height of the balloon above the ground when the angle is 60°.
Options:
(a) 40 m
(b) 60 m
(c) 80 m
(d) 100 m
✅ Answer: (d) 100 m
Explanation: Let initial height be h. tan(60°) = (h + 60)/x and tan(30°) = h/x → Solving gives h = 40 → Total height = 100 m
Q15. From the top of a building 80 m high, the angle of elevation of the top of a tower is 30°, and the angle of depression of its foot is 45°. Find the height of the tower.
Options:
(a) 80 + 80/√3 m
(b) 80 + 80√3 m
(c) 40 + 40√3 m
(d) 60 m
✅ Answer: (a) 80 + 80/√3 m
Explanation: Let distance between tower and building be x. tan(45°) = 80/x → x = 80 tan(30°) = (H − 80)/80 → H = 80 + 80/√3 m
Many students feel nervous when they hear "trigonometry," imagining complicated formulas and confusing triangles.
But in the IPMAT Trigonometry Questions 2026, the reality is simple:
You only need to understand right-angled triangles and their side-angle relationships.
No calculus. No heavy identities. Just visualization, ratios, and logic.
Trigonometry = Geometry + Ratios + Common Sense.
Once you understand the logic, every question becomes a 60-second problem.
Trigonometry questions in IPMAT appear almost every year, both in IIM Indore and IIM Rohtak question papers.
These questions generally test your understanding of angles, trigonometric ratios, identities, and real-life applications such as height and distance.
On average, you can expect 2-4 IPMAT Trigonometry Questions, each carrying equal marks.
The best part? Most of them are formula-based, meaning that if you know your basics well, these are guaranteed marks.
Understanding question patterns helps you recognize what the examiner expects.
Let's go through the most repeated types of IPMAT Trigonometry Questions with examples.
Most Frequent Topic (5-6 marks potential)
Concept: These questions involve using trigonometric ratios (sin, cos, tan) in right-angled triangles formed by vertical and horizontal lines.
Example:
A tower is 50 m high. The angle of elevation of its top from a point on the ground is 30°. Find the distance of the point from the tower's base.
Formula:
tanθ=heightbase\tan \theta = \frac{\text{height}}{\text{base}}tanθ=baseheight
Tip: Always draw a diagram and use standard triangle ratios:
30°-60°-90° → 1 : √3 : 2
45°-45°-90° → 1 : 1 : √2
Concept: A person moves towards or away from an object, changing the angle of elevation.
Example:
A man sees a tower at 30°. After walking 40 m towards it, the angle becomes 60°. Find the height of the tower.
Tip: Use two tan equations and eliminate distance to find height.
Concept: When one angle is the complement of another (θ + φ = 90°), then:
sinθ=cosϕ,tanθ=cotϕ\sin \theta = \cos \phi, \quad \tan \theta = \cot \phisinθ=cosϕ,tanθ=cotϕ
Example:
Two poles have heights 16 m and 9 m, and angles of elevation from each other's bases are complementary. Find the distance between them.
Tip: Set up:
tanθ=16x,cotθ=9x\tan \theta = \frac{16}{x}, \quad \cot \theta = \frac{9}{x}tanθ=x16,cotθ=x9
Multiply and solve → x2=144x^2 = 144x2=144, so x=12x = 12x=12.
Concept: The angle of elevation/depression of a moving object changes over time.
Example:
An airplane at 1500√3 m height changes its angle of elevation from 60° to 30° in 15 seconds. Find its speed.
Tip: Use tan θ = height / distance → Find horizontal distances for both angles, subtract to get distance covered, divide by time for speed.
Example:
If sin θ = 3/5, find cos θ and tan θ.
Solution: Use Pythagoras → cos θ = 4/5, tan θ = 3/4.
Tip: Remember the trigonometric identities:
sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1sin2θ+cos2θ=1
Concept: Simplify or prove expressions using basic trigonometric formulas.
Example:
Simplify: 1−sin2Acos2A\frac{1 - \sin^2 A}{\cos^2 A}cos2A1−sin2A
Solution: Since 1−sin2A=cos2A1 - \sin^2 A = \cos^2 A1−sin2A=cos2A, the result = 1.
Tip: These are direct formula-based questions - memorize key identities for quick wins.
Answer: 45\frac{4}{5}54
All questions are based on right-angled triangles formed between:
Trigonometric ratios define the relationship between sides and angles.
|
Ratio |
Formula |
Meaning |
|
sin θ |
P / H |
Perpendicular ÷ Hypotenuse |
|
cos θ |
B / H |
Base ÷ Hypotenuse |
|
tan θ |
P / B |
Perpendicular ÷ Base |
|
cot θ |
B / P |
Base ÷ Perpendicular |
|
sec θ |
H / B |
Hypotenuse ÷ Base |
|
cosec θ |
H / P |
Hypotenuse ÷ Perpendicular |
If you want to score high in IPMAT 2026, mastering Height and Distance problems is essential.
These problems form the backbone of IPMAT Trigonometry Questions 2026 because they combine geometry, logic, and basic trigonometry in a way that is always straightforward if approached correctly.
At their core, these problems deal with right-angled triangles formed between:
Two key angles appear in these problems:
Angle of Elevation: This is the angle formed when the observer looks upwards from their eye level to the top of an object. For example, looking at a kite in the sky or at the top of a tall tower.
Angle of Depression: This is the angle formed when the observer looks downwards from their eye-level to the bottom of an object. For instance, looking down from a balcony or the top of a building at a car on the road.
High Frequency: Almost every IPMAT paper contains at least one Height and Distance question. Sometimes it's a simple single-triangle problem, other times it involves multiple steps like moving observers, broken objects, or complementary angles.
High Accuracy Potential: These questions are purely formulaic once you visualize the triangle correctly. Students who practice these can often solve them in under 2 minutes, making them some of the highest-scoring questions in Quantitative Aptitude.
Foundational for Other Problems: Understanding these problems also helps with motion problems (like airplanes or cranes) and complementary angles between pillars or towers.
|
Term |
Explanation |
|
Angle of Elevation |
The angle formed when the observer looks upward from the horizontal line. |
|
Angle of Depression |
The angle formed when the observer looks downward from the horizontal line. |
|
Line of Sight |
The imaginary line connecting the observer's eye and the object. |
Ratio → 1 : √3: 2 If the side opposite 30° = x → Opposite 60° = x√3 → Hypotenuse = 2x
Remember: 30° → smallest side 60° → medium side 90° → longest side
Ratio → 1: 1: √2 If one perpendicular = x → Other = x → Hypotenuse = x√2
Remember: Both perpendicular sides are equal in a 45° triangle.
|
θ |
sin θ |
cos θ |
tan θ |
|
0° |
0 |
1 |
0 |
|
30° |
1/2 |
√3/2 |
1/√3 |
|
45° |
1/√2 |
1/√2 |
1 |
|
60° |
√3/2 |
1/2 |
√3 |
|
90° |
1 |
0 |
∞ |
"Every IPMAT height and distance question is just a variation of a single right triangle."
So instead of memorizing formulas, focus on visualizing the triangle:
Once you can answer those, the formula reveals itself automatically.
"Draw before you solve. Always."
Visualization is your secret weapon.
In the IPMAT Trigonometry Questions 2026, most students lose marks not because they can't calculate - but because they can't see the triangle.
Once you can picture the right triangle, you'll find that every trigonometry question - from a kite to an airplane- is just a familiar friend.
The IPMAT Trigonometry Questions 2026 aren't meant to test how many formulas you remember; they test how well you can think geometrically.
|
Type |
Expected No. of Questions |
Difficulty |
Marks |
|
Height & Distance |
1-2 |
Moderate |
4-8 |
|
Ratio Simplification |
1 |
Easy |
4 |
|
Complementary Angles |
1 |
Easy |
4 |
Total: 3-4 questions, worth 12-16 marks - extremely high scoring if prepared well.
|
Formula |
Used When |
Example |
|
sinθ = P/H |
Height with hypotenuse |
Kite problem |
|
tanθ = P/B |
Height with base |
Tower & man |
|
tan(90°−θ)=cotθ |
Complementary angles |
Two pillars |
|
Speed = Distance/Time |
Motion |
Airplane problem |
Frequently Asked Questions
What topics are most common in IPMAT Trigonometry Questions 2026?

How important are Trigonometry questions for IPMAT 2026?

Can IPMAT Trigonometry Questions 2026 questions be solved without diagrams?

Are there shortcuts for special triangles in Trigonometry Questions 2026?

How should I approach moving observer problems in IPMAT Trigonometry Questions 2026?

How much time should I spend on each question in IPM Trigonometry Questions 2026?

What is the final strategy for IPMAT Trigonometry Questions 2026?

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