July 27, 2026
Quick Answer: CAT successive discounts questions test what happens when two or more discounts are applied one after another, with each discount acting on the price left after the previous one. Two successive discounts of a% and b% equal a single discount of (a + b - ab/100)%, which is always less than a + b. So 20% followed by 10% is a 28% discount, not 30%.
The fastest exam method is multiplicative: multiply the marked price by (1 - a/100) × (1 - b/100). In CAT 2026, expect this concept inside a profit-and-loss question involving markup on cost price rather than on its own. That is exactly where most aspirants lose the mark.
In CAT exam successive discount is a discount applied to an already-discounted price.
When a store advertises "40% off, plus an extra 10% off at checkout," the second 10% is not taken on the original tag price. It is taken on the 60% that remains. That single detail is the whole topic. It is also why the shopper saves 46% rather than 50%.
Worked Example: The ₹4,000 Jacket
Consider a jacket marked at ₹4,000 with successive discounts of 40% and 10%.
| Step | Calculation | Amount |
|---|---|---|
| Marked Price (MP) | - | ₹4,000 |
| First discount (40%) | 40% of 4,000 | ₹1,600 |
| Price after first discount | 4,000 - 1,600 | ₹2,400 |
| Second discount (10%) | 10% of 2,400 | ₹240 |
| Selling Price (SP) | 2,400 - 240 | ₹2,160 |
| Total discount | 4,000 - 2,160 | ₹1,840 |
| Equivalent single discount | 1,840 / 4,000 | 46% |
The second discount was worth ₹240 instead of ₹400 because it operated on a smaller base. That ₹160 difference, as a percentage of MP, is 4%. And 4 is exactly (40 × 10)/100.
CAT successive discounts questions are one of the most practical and scoring topics in the Arithmetic section of CAT Quantitative Aptitude. While direct questions are rare, the concept is frequently embedded in Profit & Loss, Percentage, and Marked Price problems, making it an essential topic for CAT 2026 preparation.
A strong understanding of CAT successive discounts questions helps you:
If you are aiming for a high percentile, practising Successive Discounts Questions for CAT should be a part of your regular Arithmetic revision. You can also download the CAT successive discounts questions PDF for offline practice and revision before the exam.
As per the CAT exam pattern, the Quantitative Aptitude section carries 22 questions in 40 minutes. Each correct answer earns 3 marks and each incorrect MCQ costs 1 mark. In CAT 2025, the split was 14 MCQs and 8 TITA questions, where TITA carries no negative marking.
Within QA, the CAT Arithmetic syllabus has consistently been the largest contributor in recent years. That block covers percentages, profit and loss, ratios, averages, time and work, and time-speed-distance.
Formula for Two Successive Discounts
For discounts of a% and b% applied successively, the equivalent single discount is:
D = a + b - (ab / 100)
Derivation: Take MP = 100.
After the first discount the price becomes:
100 - a
After the second discount:
(100 - a) × (1 - b/100)
Expanding gives:
100 - a - b + ab/100
Therefore, the total discount becomes:
a + b - ab/100
Formula for Three Successive Discounts
For three successive discounts of a%, b%, and c%, the equivalent single discount is:
D = a + b + c - (ab + bc + ca)/100 + (abc/10,000)
For example, if the discounts are 10%, 20%, and 30%:
D = 60 - (200 + 600 + 300)/100 + 6000/10000 = 49.6%
While the formula is useful to know, it becomes lengthy during the exam. The multiplicative-factor method is much faster and less prone to calculation errors.
The Multiplicative Factor Method
The fastest way to solve CAT successive discount questions is by using discount factors.
Selling Price = Marked Price × (1 - d₁/100) × (1 - d₂/100) × (1 - d₃/100)...
For example, if the discounts are 10%, 20%, and 30%:
Factor = 0.9 × 0.8 × 0.7 = 0.504
The customer pays 50.4% of the marked price.
Equivalent Discount = 49.6%.
This method immediately proves that the order of discounts never matters because multiplication is commutative.
Multiplication Factors Worth Memorising
| Discount | Decimal Factor | Fraction |
|---|---|---|
| 5% | 0.95 | 19/20 |
| 6.25% | 0.9375 | 15/16 |
| 10% | 0.90 | 9/10 |
| 12.5% | 0.875 | 7/8 |
| 16.67% | - | 5/6 |
| 20% | 0.80 | 4/5 |
| 25% | 0.75 | 3/4 |
| 33.33% | - | 2/3 |
| 37.5% | 0.625 | 5/8 |
| 40% | 0.60 | 3/5 |
| 50% | 0.50 | 1/2 |
Using fractions instead of decimals often makes calculations significantly faster during the CAT exam.
These combinations should become instant mental calculations.
| Successive Discounts | Equivalent Single Discount |
|---|---|
| 5% + 5% | 9.75% |
| 10% + 5% | 14.5% |
| 10% + 10% | 19% |
| 15% + 15% | 27.75% |
| 20% + 5% | 24% |
| 20% + 10% | 28% |
| 20% + 20% | 36% |
| 25% + 10% | 32.5% |
| 25% + 20% | 40% |
| 25% + 25% | 43.75% |
| 30% + 10% | 37% |
| 30% + 20% | 44% |
| 30% + 30% | 51% |
| 40% + 10% | 46% |
| 40% + 40% | 64% |
| 50% + 10% | 55% |
| 50% + 20% | 60% |
| 10% + 10% + 10% | 27.1% |
| 20% + 20% + 20% | 48.8% |
Notice that 30% + 10% gives a larger overall discount than 20% + 20%, even though both total 40 percentage points.
Q1. An article marked at ₹2,400 is sold after successive discounts of 20% and 15%. Find the selling price and the equivalent single discount.
Approach: Use multiplication factors.
SP = 2400 × 0.80 × 0.85
= 2400 × 0.68
SP = ₹1,632
The customer pays 68% of the marked price.
Equivalent Discount = 32%
Formula check:
20 + 15 - (20 × 15)/100
= 35 - 3
= 32%
Q2. Find the single discount equivalent to three successive discounts of 10% each.
Approach: Multiplication factors.
Factor = 0.9 × 0.9 × 0.9
= 0.729
Equivalent Discount
= 1 - 0.729
= 27.1%
Three successive 10% discounts are not equal to a 30% discount.
Q3. An item with a marked price of ₹5,000 sells for ₹3,375 after two successive discounts. If the first discount is 25%, find the second discount.
After the first discount:
5000 × 0.75 = ₹3750
Second factor = 3375 / 3750
= 0.90
Second Discount = 10%
Q4. Which is the better deal for a buyer: a flat 30% discount, or successive discounts of 20% and 12%?
Equivalent discount
= 20 + 12 - (20 × 12)/100
= 32 - 2.4
= 29.6%
Therefore, the flat 30% discount is slightly better.
Q5. After two successive discounts of 20% and 25%, an article sells for ₹1,800. Find its marked price.
Combined factor
= 0.80 × 0.75
= 0.60
Marked Price
= 1800 / 0.60
= ₹3,000
Q6. A shopkeeper marks his goods 45% above cost price and offers successive discounts of 10% and 10%. Find his profit percentage.
Assume Cost Price = ₹100.
Marked Price = ₹145.
Selling Price = 145 × 0.9 × 0.9
= ₹117.45
Profit = 17.45%
Q7. A trader allows two successive discounts of 20% and 10% and still earns a profit of 8%. By what percentage above cost price are his goods marked?
Assume Cost Price = ₹100.
Selling Price = ₹108.
MP × 0.80 × 0.90 = 108
MP × 0.72 = 108
MP = ₹150
Markup = 50%
Q1. An article marked at ₹2,400 is sold after successive discounts of 20% and 15%. Find the selling price and the equivalent single discount.
Approach: Use factors because both answers are required.
SP = 2,400 × 0.80 × 0.85 = 2,400 × 0.68 = ₹1,632
The customer pays 68% of the marked price, so the equivalent discount is 32%.
Formula Check:
20 + 15 − (20 × 15)/100 = 35 − 3 = 32%
Q2. Find the single discount equivalent to three successive discounts of 10% each.
Approach: Factor method.
0.9 × 0.9 × 0.9 = 0.729
Equivalent Discount = 1 − 0.729 = 27.1%
Q3. An item with a marked price of ₹5,000 sells for ₹3,375 after two successive discounts. If the first discount is 25%, find the second.
Solution:
After first discount:
₹5,000 × 0.75 = ₹3,750
Second factor:
3375 ÷ 3750 = 0.90
Second Discount = 10%
Q4. Which is the better deal: Flat 30% discount or successive discounts of 20% and 12%?
Equivalent discount:
20 + 12 − (20 × 12)/100
= 32 − 2.4
= 29.6%
Winner: Flat 30% discount.
Q5. After successive discounts of 20% and 25%, an article sells for ₹1,800. Find the marked price.
Combined factor:
0.80 × 0.75 = 0.60
Marked Price = 1800 ÷ 0.60 = ₹3,000
Q6. A shopkeeper marks goods 45% above cost and offers discounts of 10% and 10%. Find the profit percentage.
Assume CP = 100
MP = 145
SP = 145 × 0.9 × 0.9
= 145 × 0.81
= 117.45
Profit = 17.45%
Q7. A trader allows successive discounts of 20% and 10% and still earns 8% profit. Find the markup.
Assume CP = 100
SP = 108
MP × 0.8 × 0.9 = 108
MP × 0.72 = 108
MP = 150
Markup = 50%
Q8. Two successive discounts, where the second is twice the first, equal a single discount of 28%. Find both discounts.
Let first discount = d
Second discount = 2d
(1 − d)(1 − 2d) = 0.72
2d² − 3d + 0.28 = 0
d = 10%
Therefore discounts are:
Q9. A product's list price increases by 25%, then receives discounts of 10% and 20%. Find the net change.
Net factor:
1.25 × 0.90 × 0.80 = 0.90
Final price is 10% below the original list price.
Q10. A dealer buys an article at a 30% discount and sells it at a 5% discount on the same list price. Find profit percentage.
Assume List Price = 100
CP = 70
SP = 95
Profit = (95 − 70)/70 × 100
= 25/70 × 100
= 35.71%
Q11. Two stores offer different discounts on an ₹8,000 article.
Store A: 25% + 15%
Factor = 0.75 × 0.85 = 0.6375
SP = ₹5,100
Store B: 30% + 10%
Factor = 0.70 × 0.90 = 0.63
SP = ₹5,040
Store B is cheaper by ₹60.
Most CAT successive discounts questions follow a predictable pattern. Once you learn the correct approach, these questions become some of the quickest marks in the QA section.
Step 1: Identify the marked price
Read the question carefully and determine whether the given price is the Marked Price (MP), Cost Price (CP), or Selling Price (SP).
Step 2: Convert discounts into multiplication factors
Instead of subtracting percentages repeatedly, use factors.
For successive discounts of 20% and 10%:
Selling Price = MP × 0.80 × 0.90
= MP × 0.72
Therefore, the equivalent discount is 28%.
Depending on the question, calculate:
Whenever possible, multiply the factors again to ensure your calculations are correct. This simple verification method reduces silly mistakes in CAT successive discounts questions.
For additional practice, solve more Successive Discounts Questions for CAT and revise regularly using the CAT successive discounts questions PDF.
Learning a few shortcut techniques can help you solve CAT successive discounts questions much faster during the exam.
For two successive discounts of a% and b%:
Equivalent Discount = a + b − (ab/100)
Example:
20% and 10%
= 20 + 10 − (20 × 10)/100
= 30 − 2
= 28%
Instead of remembering formulas, simply multiply the remaining value.
Example:
25% and 20%
= 0.75 × 0.80
= 0.60
Equivalent discount = 40%
This is the fastest method for solving CAT successive discounts questions involving multiple discounts.
Some combinations appear repeatedly in exams.
| Successive Discounts | Equivalent Discount |
|---|---|
| 10% + 10% | 19% |
| 20% + 10% | 28% |
| 20% + 20% | 36% |
| 25% + 20% | 40% |
| 30% + 10% | 37% |
| 40% + 10% | 46% |
| 50% + 20% | 60% |
20% + 10% is not 30%.
Always calculate the second discount on the reduced price.
Confusing these two bases is the most common mistake in Successive Discounts Questions for CAT.
Although direct CAT successive discounts questions do not appear every year, the concept has consistently been tested through mixed Arithmetic questions involving Profit & Loss, Marked Price, and Percentages. Instead of asking only for the equivalent discount, CAT generally combines successive discounts with one or more additional concepts.
Some of the most common previous-year patterns include:
The best way to prepare for these questions is by solving Successive Discounts Questions for CAT from previous CAT papers and topic-wise practice sets. Rather than memorising formulas alone, focus on identifying the correct multiplication factors and applying them quickly under time pressure.
For structured revision, download the CAT successive discounts questions PDF, which contains solved examples, previous-year style questions, shortcut techniques, and practice exercises to strengthen your preparation. By consistently practising CAT successive discounts questions, you will improve both your calculation speed and your accuracy in the Arithmetic section.
The concept is common across MBA entrances in the 2026-27 cycle, but the testing style differs. These exams should not be prepared for interchangeably. A fuller breakdown sits in CAT vs XAT vs SNAP vs NMAT.
The practical implication is worth stating plainly. The concept transfers fully across all five exams. The practice strategy does not. So drill the topic once for concept, then re-practise it inside each exam's own sectional format and timing. Confirm current section names, question counts and timings against each exam's official 2026 notification before finalising a plan.
Topic practice builds mechanics. It cannot reproduce the two conditions that make CAT difficult: mixed-topic sequencing and a 40-minute clock. Twenty discount questions in a row build a pattern recognition that evaporates the moment the same question turns up as question 14, sandwiched between a Geometry problem and a quadratic.
So use this sequence. Finish the practice set above. Download the PDF and drill it to reliability. Then move straight to a timed sectional mock test for CAT on Arithmetic. Afterwards, read your own paper properly, because how to analyse CAT mock tests explains how to separate a concept gap from a setup error. That distinction is what actually moves a percentile.
Topic-level practice establishes the skill. Sectional and full-length testing converts it into a score.
CAT successive discounts questions are among the highest ROI topics in Arithmetic because the underlying concept is simple, repeatable, and directly applicable to several other chapters like compound interest, depreciation, and percentage change. Rather than memorising formulas alone, focus on understanding the multiplicative-factor approach while practicing CAT sample papers, the distinction between cost price and marked price, and the sequence in which discounts are applied.
With regular practice, these questions can become some of the quickest marks in the Quantitative Aptitude section. Master the factor method, revise the reference table, avoid the common mistakes discussed above, and solve enough mixed Arithmetic questions to recognise the pattern instantly in the exam.
Finally, don't stop at theory. Attempt sectional tests, analyse every mistake, and revisit this topic during your final revision cycle. Consistency in practice is what converts a concept into a percentile-boosting strength on CAT 2026.
Frequently Asked Questions
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