Author : Akash Kumar Singh
August 13, 2026
SHARE
Explanation:
(18) 1800 = 2^3 ×3^2 ×5^2
=2×3 x (2^2×3^1×5^2)
= 6 x (2^2 ×3^1 ×5^2)
Number of factors of 1800 which are also multiple of 6
= Number of factors of the highlighted part of the number
= (2 +1)(1+1)(2+1) = 3×2×3=18. Ans
Attempt a Free IPMAT Mock Test
Fill your details
Recently Published
IIMB UG Exam Day Instructions (2027): Complete Rules, Checklist & Prohibited Items
Updated On : November 3, 2026
IIM Bangalore UG Exam Analysis 2027: Section-wise Difficulty, Good Attempts & Cutoff (UG-AT)
IIMB BSc Data Science Exam Pattern 2027: Complete Guide
IIMB UG Entrance Exam Preparation 2027: Study Plan and Tips
IIMB UG Entrance Exam 2027: Dates, Registration, Pattern, Eligibility & Selection
IIM Bangalore UG Important Topics 2027: Section-Wise Priority & Weightage
MAH BMS BBA CET 2027 Admit Card: Release Date, How to Download, Details
How to Prepare for MAH BBA CET Exam 2027 [Tips to Prepare]
MAH BBA CET Important Topics 2027: English, Reasoning, GK, Computer + Study Plan
MAH BMS BBA CET Result 2027: Expected Date, Scorecard, Marks vs Percentile & CAP Dates
SHARE