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IPMAT Indore 2023 - QA (MCQ) Q40 Explanation
December 31, 2024
Explanation:
(d)
10^2023 = 2^2023 × 5^2023
Total positive divisors = (2023+1) × (2023+1)
= 2024 x 2024 = (2024)^2
Now the number of divisors of 10^2023 which are also the multiple of 102001 can be find out by counting the total number of divisors of 1022 in 102023 i.e. 10^2001 x 10^22
∴ Total number of divisors of 1022 i.e. 5^22 x 2^22 will be equal to (22+1) × (22+1) = 23 x 23 = (23)^2
So, Probability = 23^2/2024^2 Ans.
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