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IPMAT Indore 2023 - QA (MCQ) Q17 Explanation
December 30, 2024
Explanation:
(a)
Let the radius of large ball = ‘R’
Let the radius of each bead = R/5
Number of beads = Volume of large ball/Volume of one bead
= 4/3π R^3 / 4/3π (R/5)^3 = 125
Given, cost price of the large ball = INR 1,000,000
So, the cost price of each ball = INR 1,000,000/125 = INR 8000
Profit earned on each bead is 20%. (given)
So, the selling price of each bead = INR 8000 x 1.2 = INR 9600….eq.(1)
Let the list price of each bead = INR ‘x’.
∴ 𝑥𝑚𝑖𝑛𝑖𝑚𝑢𝑚 = 8 Ans.
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