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IPMAT Indore 2022 - QA (MCQ) Q36 Explanation
December 28, 2024
Explanation:
(b)
In ∆DAB, tan45° = P/B = 200m/AB
⇒ 𝐴𝐵 = 200𝑚.
In ∆DAC, tan30° = 200/AC = 200/200+BC
1/√3 = 200/200+𝐵𝐶
⇒ 𝐵𝐶 = 200(√3−1)
= 200 × 0.72
= 144m (approx.)
This distance 144m is travelled by the car in 2 min.
∴ speed of car = 144m/2 min = (144/1000 ) (60/2)
= 4.39 km/h.
Thus, speed of car is 4.39 km/h.
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