Updated On : January 17, 2023
Time and Work is one of the most familiar quantitative aptitude topics which is asked in the CLAT examination. This is one of those topics which candidates are familiar with even before they start their CLAT exam preparation.
The concept of time and work remains the same, however, the type of questions asked may have a portion which varies in every question.
Mostly, in CLAT (Common Law Admission Test) examination 1-2 word problems are asked from this topic but candidates must also keep themselves prepared to have questions in data sufficiency and data interpretation to be picked up from time and work.
Before we start understanding the questions and important formulas, it is crucial that a candidate is well aware of the concept and the types of questions which may be asked in the CLAT examination.
Time and work deals with the time taken by an individual or a group of individuals to complete a piece of work and the efficiency of the work done by each of them.
Work to be done is generally considered as one unit, it may be digging a bench, constructing or painting a wall, filling up or emptying a tank, reservoir or a cistern.
Now, below you will get to know the important information that will help you to solve Time and Work related questions.
Thus, Work (W) = Time (T) x Rate of Work (R).
Thus, R = 1 / T.
For example, If a person can do some work in 12 days then it means he does 1 / 12th of the work in one day.
For example, If a person’s one day of work is 1 / 10, then he can finish the whole work in 10 days.
Important Maths Formulas for CLAT 2024
For example, If a man works two times as fast as a woman does, then on completion of the work 2 parts of the work has been done by the man and 1 part by the woman. Also, if they work individually then the woman takes 10 days to complete the work and the man takes 5 days to complete the work.
Below mentioned are the type of questions which may be asked in the Common Law Admission Test (CLAT) from the time and work topic: -
In this article, you will get all the types of questions that are asked in the time and work topic in the common law admission test (CLAT).
How to Attempt Quant Section in CLAT 2024
Question 1: A can do a piece of work in 10 days and B can do the same work in 30 days. In how many days can the work be completed if A and B work together?
(1). 4 5 / 2
(2). 7 1 / 2
(3). 6 9 / 5
(4). 2 3 / 5
(5). None of these
Answer: (2) 7 1 / 2
Explanation:
To Given: A’s 1 day’s work = 1 / 10
B’s 1 day work = 1 / 30
To Find: How many days can the work be completed if A and B work together?
Solution:
A’s 1 day’s work = 1 / 10
B’s 1 day work = 1 / 30
Therefore,
(A + B)’s 1 day’s work = 1 / 10 + 1 / 30
(A + B)’s 1 day’s work = 2 / 15
Hence, A and B together can do the work in 15 / 2 days, i.e. 7 1 / 2 days.
Question 2: A and B together can do a piece of work in 9 days. ‘A’ Alone can complete the work in 12 days. How long will B alone take to complete the job?
(1). 30 days
(2). 50 days
(3). 60 days
(4). 36 days
(5). 20 days
Answer: (4) 36 days
Explanation:
To Given: (A + B)’s 1 day’s work = 1 / 9
A’s Alone 1 day’s work = 1 / 12
To Find: B’s Alone 1 day’s work?
Solution:
(A + B)’s 1 day’s work = 1 / 9
A’s Alone 1 day’s work = 1 / 12
Therefore,
B’s Alone 1 day’s work = 1 / 9 - 1/ 12
B’s Alone 1 day’s work = 1 / 36.
So, B alone can do the work in 36 days.
Question 3: A can do work in 25 days. When he had worked for 15 days, B replaced him. If he completes the remaining work in 10 days, in how many days can B alone finish the work?
(1). 20 days
(2). 10 days
(3). 30 days
(4). 40 days
(5). None of these
Answer: (5) None of these
Explanation:
To given: A’s 1 day’s work = 1 / 25
A’s 15 day’s work = 15 / 25
To find: In how many days can B alone finish the work?
Solution:
A’s 1 day’s work = 1 / 25
A’s 15 day’s work = 15 / 25
A’s 15 day’s work = 3 / 5
Work remaining = (1 - 3 / 5) = 2 / 5 which is done by B in 10 days.
Therefore,
B can do the work alone in (5 / 2 x 10) = 25 days
Question 4: A is thrice as good a workman as B and is therefore able to finish a piece of work in 30 days less than B. Find the time in which they can do it working together.
(1). 11 1 / 4
(2). 5 2 / 3
(3). 6 2 / 3
(4). 20 4 / 2
(5). None of these.
Answer: (1). 11 1 / 4
Explanation:
To given: A is thrice as good as workman as B
To find: the time in which they can do it working together?
Solution:
The ratio of work done by A and B in the same time = 3 : 1
Ratio of time taken by A and B = 1 : 3
Let B takes π₯ days to finish a work.
Then,
A takes (π₯ - 30) days to finish it.
Therefore,
⇒ π₯ - 30 / π₯ = 1 / 3
⇒ 3π₯ - 90 = π₯
⇒ π₯ = 45 days
Thus, A and B can finish the work in 15 days and 45 days, respectively.
Now, (A + B)’s 1 day’s work = 1 / 15 + 1 / 45 = 4 / 45.
So, both together can finish the work in 45 / 4 days = 11 1 / 4 days.
Attempt Short Quiz on Time and Work for CLAT 2024
Question 5: 1 woman or 2 men or 3 boys can do a piece of work in 55 days, then the same piece of work will be done by 1 man, 1 woman and 1 boy in how many days?
(1). 18 days
(2). 30 days
(3). 32 days
(4). 16 days
(5). None of these
Answer: (2) 30 days
Explanation:
To given: 1 woman = 2 man = 3 boys
To find: the same piece of work will be done by 1 man, 1 woman and 1 boy in how many days?
Solution:
1 woman = 2 man = 3 boys
⇒ 1 boy = 2 / 3 man.
⇒ 1 man + 1 woman + 1 boy = 1 man + 2 men + 2 / 3 men
⇒ (1 + 2 + 2 / 3) = 11 / 3 men.
If 2 men can do work in 55 days.
Then,
⇒ 11 / 3 men will do the same work in = 2 x 55 x 3 / 11 = 30 days.
So, 1 man, 1 woman, and 1 boy will completer the same piece of work in 30 days
Question 6: If 5 men and 2 boys are working together, can do three times as much work per hour as a man and a boy together. The ratio of the work done by a man and that of a boy for a given time is
(1). 1 : 2
(2). 2 : 1
(3). 1 : 3
(4). 3 : 1
(5). None of these
Answer: (1) 1 : 2
Explanation:
To given: 5 men and 2 boys are working together, and can do three times as much work per hour as a man and a boy together.
To find: ratio of the work done by a man and that of a boy for a given time
Solution:
⇒ 5 men + 2 boy = 3 (1 man + 1 boy)
⇒ 5 men + 2 boy = 3 men + 3 boy
⇒ 2 men = 1 boy
Therefore,
The required ratio of work done by a man and a boy = 1 : 2
Question 7: If 2 men and 3 boys can do a piece of work in 16 days and 3 men and 2 boys can do it in 14 days, how long will 5 men and 4 boys take to do it?
(1). 6 days
(2). 8 days
(3). 9 days
(4). 10 days
(5). None of these
Answer: (2) 8 days
Explanation:
To given: 2 men and 3 boys can do a piece of work in 16 days and 3 men and 2 boys can do it in 14 days.
To find: how long will 5 men and 4 boys take to do it?
Solution:
⇒ 2 men + 3 boys = 16 days
⇒ 2 x 16 men + 3 x 16 boys = 1 day
⇒ 32 men + 48 boys = 1 day …………….. Equation (1)
And
⇒ 3 men + 2 boy = 14 days
⇒ 42 men + 28 boys = 1 day ………….. Equation (2)
On solving Equation (2), we get
⇒ 1 men = 2 boys
⇒ 2 men + 3 boys = 4 boys + 3 boys
⇒ 2 men + 3 boys = 7 boys
And
⇒ 5 men + 4 boys = 10 boys + 4 boys
⇒ 5 men + 4 boys = 14 boys
Now, 7 boys take = 16 days
Therefore,
⇒ 14 boys take = 16 x 7 / 14
⇒ 14 boys take = 8 days
Question 8: A and B complete a piece of work in 5 days working together. If A had worked twice the work would have been completed in 4 days. In how many days can A alone complete the work?
(1). 20 days
(2). 18 days
(3). 24 days
(4). 15 days
(5). None of these
Answer: (1). 20 days
Explanation:
To given: A and B complete a piece of work in 5 days working together.
To find: In how many days can A alone complete the work?
Solution:
Let A do the work in ‘a’ days.
A’s 1 day’s work = 1 / a
Let B do the work in ‘b’ days.
B’s 1 day’s work = 1 / b
Now,
⇒ 1 / a + 1 / b = 1 / 5 …………… Equation (1)
⇒ 2 / a + 1 / b = 1 / 4 ……………. Equation (2)
By solving Equation (1) and Equation (2), we get
⇒ a = 20 days.
Hence, A alone will complete the work in 20 days.
Question 9: If I must hire 6 men and 8 boys for 6 days to do the same piece of work as 8 men and 15 boys could do in 4 days, compare the efficiency ratio of the men and the boys.
(1). 1 : 2
(2). 1 : 3
(3). 1 : 4
(4). 1 : 5
(5). None of these
Answer: (5). None of these
Explanation:
To given: 6 men + 8 boys can do a piece of work in 6 days
8 men + 15 boys can do a piece of work in 4 days
To find: compare the efficiency ratio of the men and the boys.
Solution:
⇒ (6 men + 8 boys) can do a piece of work in 6 days
⇒ (8 men + 15 boys) can do a piece of work in 4 days
⇒ (6 men + 8 boys) can do a piece of work in 6 days
⇒ (36 men + 48 boys) can do the work in 1 day
⇒ (8 men + 15 boys) can do a piece of work in 4 days
⇒ (32 men + 60 boys) can do the work in 1 day
⇒ 36 men + 48 boys = 32 men + 60 boys
⇒ 36 men - 32 men = 60 boys - 48 boys
⇒ 4 men = 12 boys
⇒ men = 3 boys
Therefore, the ratio of efficiency of men and boys = 3 : 1.
Question 10: 3 men or 5 women can do work in 6 days. How long will 6 men and 5 women take to finish the work?
(1). 2.5 days
(2). 2 days
(3). 3 days
(4). 3.5 days
(5). None of these
Answer: (2). 2 days
Explanation:
To given: 3 men or 5 women can do work in 6 days
To find: How long will 6 men and 5 women take to finish the work?
Solution:
3 men = 5 women
Or
⇒ 3 x 5 x 6 / (3 x 5 + 6 x 5)
⇒ 3 x 5 x 6 / 45 = 2
⇒ 1 man = 5 / 3 women
⇒ 6 men + 5 women = (6 x 5 / 3 + 5)
⇒ women = 15 women.
Now, if 5 women can do work in 6 days.
⇒ 15 women can do it in (5 x 6 / 15) days = 2 days
Hence, 6 men and 5 women will take 2 days to finish the work.
Question 11: 4 men can do a piece of work in 10 days, 2 women can do it in 15 days and 5 children can do it in 12 days. In how many days can 8 men, 5 women and 15 children together complete the piece of work?
(1). 2 days
(2). 3 days
(3). 4 days
(4). 5 days
(5). None of these
Answer: (5) None of these
Explanation:
To given: 4 men’s 1 day’s work = 1 / 10.
1 man’s 1 day’s work = 1 / 40.
2 women’s 1 day’s work = 1 / 15.
1 woman’s 1 day’s work = 1 / 30.
5 children’s 1 day’s work = 1 / 12.
1 child’s 1 day’s work = 1 / 60.
To find: In how many days can 8 men, 5 women and 15 children together complete the piece of work?
Solution:
⇒ 4 men’s 1 day’s work = 1 / 10.
⇒ 1 man’s 1 day’s work = 1 / 40.
⇒ 2 women’s 1 day’s work = 1 / 15.
⇒ 1 woman’s 1 day’s work = 1 / 30.
⇒ 5 children’s 1 day’s work = 1 / 12.
⇒ 1 child’s 1 day’s work = 1 / 60.
Now,
⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 8 / 40 + 5 / 30 + 15 / 60
⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 1 / 5 + 1 / 6 + 1 / 4
⇒ (8 men + 5 women + 15 children)’s 1 day’s work = 37 / 60.
So, they can finish the work in 60 / 37 days.
Question 12: 3 men can do a piece of work in 12 days, 5 women in 8 days and 20 children in 3 days. In how many days can a man, a woman, and a child work together to complete the piece of work?
(1). 12 days
(2). 13 days
(3). 14 days
(4). 15 days
(5). None of these
Answer: (5). None of these
Explanation:
To given: 3 men can do a piece of work in 12 days
5 women can do a piece of work in 8 days.
20 children can do a piece of work in 3 days.
To find: In how many days can a man, a woman, and a child work together to complete the piece of work?
Solution:
⇒ 3 men can do a piece of work in 12 days
⇒ 1 man will do the same piece of work in 36 days.
⇒ 5 women can do a piece of work in 8 days.
⇒ 1 woman will do the same piece of work in 40 days
⇒ 20 children can do a piece of work in 3 days.
⇒ 1 child will do the same piece of work in 60 days.
Now,
⇒ (1 man + 1 woman + 1 child)’s 1 day’s work = 1 / 36 + 1 / 40 + 1 / 60
⇒ (1 man + 1 woman + 1 child)’s 1 day’s work = 5 / 72.
So, the work is complete in 72 / 5 days = 14 2 / 5 days
Question 13: A certain number of men can complete a piece of work in 40 days. If there were 8 men more the work could be finished in 10 days less. How many men were there afterwards?
(1). 32 men
(2). 28 men
(3). 24 men
(4). 15 men
(5). None of these
Answer: (1). 32 men
Explanation:
Let the number of men be π₯.
π₯ men can do a work in 40 days.
(π₯ + 8) men can do the same work in (40 - 10) = 30 days.
⇒ π₯ x 40 = 30 (π₯ + 8)
⇒ 40π₯ = 30π₯ + 240
⇒ 40π₯ - 30π₯ = 240
⇒ 10π₯ = 240
⇒ π₯ = 24.
Therefore,
The number of men afterwards = 24 + 8 = 32 men
Question 14: If A can d0 ¼ of the work in 4 days and B can do β of the work in 3 days, how much will A get if both work together and are paid Rs. 4,500 in all?
(1). Rs. 1,800
(2). Rs. 2,400
(3). Rs. 2,700
(4). Rs. 2,900
(5). None of these
Answer: (3). Rs. 2,700
Explanation:
Whole work is done by A in (4 x 4) days = 16 days
Whole work is done by Bin (8 x 3) days = 24 days.
A’s wages : B’s wages
⇒ A’s 1 day’s work : B’s 1 day's work
⇒ 1/16 : 1/24
⇒ 3 : 2
Therefore,
⇒ A’s sheet = (β x 4,500)
⇒ A’s sheet = Rs. 2,700.
Question 15: 6 men can complete a piece of work in 12 days. 8 women can do the same piece of work in 18 days whereas 18 children can complete it in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day, how many men would be required totally?
(1). 36 men
(2). 24 men
(3). 18 men
(4). Cannot be determined
(5). None of these
Answer: (1). 36 men
Explanation:
⇒ (6 x 12) men = (8 x 18) women = (18 x 10) children.
⇒ 2 men = 4 women = 5 children
Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 men
⇒ 6 men’s 1 day’s work = 1/12
⇒ 18 men’s 1 day’s work = 1/12 x 18/6 = ¼
⇒ 18 men’s 2 day’s work = ¼ x 2
⇒ 18 men’s 2 day’s work = ½
Therefore,
The remaining work = 1 - ½
⇒ remaining work = ½
Remaining work can be complete by 18 men in 2 days
Therefore, to complete in 1 day, men required = 2 x 18 = 36 men
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